python noob的位和我需要在我的代码中添加正则表达式,但无法让它工作:/我搜索了谷歌的错误消息和试图找出什么是错的,但没有运气,所以我想下一个最好的事情是直接问。 这是迄今为止代码:TypeError:'int'对象不可调用在Python中
# allows us to access a random 'key' in the dictionary
import random
import re
# Contains the question and it's correct answer
my_dict = {
"A form of Protectionism that imposes a tax on imports" : "tariff",
"....is quantity of a good or service that consumers are willing and able to buy at a given price in a given time period" : "Demand",
"....is the quantity of a good or service that a producer is willing and able to supply onto the market at a given price in a given time period" : "Supply",
"By using ..... businesses can bring down their average costs by producing on a larger scale" : "Economies of scale",
"The cost of the next best alternative" : "Opportunity Cost",
".... is the transfer of assets from the public (government) sector to the private sector." : "Privatisation"
}
# welcome message
print("Economics Revision App")
print("=======================")
# the quiz will end when this variable becomes 'False'
playing = True
# While the game is running
while playing == True:
# set the score to 0
score = 0
# gets the number of questions the player wants to answer
num = int(input("\nHow many questions would you like: "))
num = re.match("r\d[0-9]{2}$", num())
if match:
print ('foo')
# loop the correct number of times
for i in range(num):
# the question is one of the dictionary keys, picked at random
question = (random.choice(list(my_dict.keys())))
# the answer is the string mapped to the question key
answer = my_dict[question]
# print the question, along with the question number
print("\nQuestion " + str(i+1))
print(question + "?")
# get the user's answer attempt
guess = input("> ")
# if their guess is the same as the answer
if guess.lower() == answer.lower():
# add 1 to the score and print a message
print("Correct!")
score += 1
else:
print("Incorrect guess again!")
# after the quiz, print their final score
print("\nYour final score was " + str(score))
# store the user's input...
again = input("Enter any key to play again, or 'q' to quit.")
#... and quit if they types 'q'
if again.lower() == 'q':
playing = False
的代码我挣扎与问题
接下来最好的事情是查看堆栈跟踪异常以查看发生错误的行。你认为'num()'在行中的含义是:num = re.match(“r \ d [0-9] {2} $”,num())'? –