我有这个和平的Javascript代码。我有一张照片,我想在mouseover上执行一个imageflip。 在浏览器中显示它,显示原始图像。当我将鼠标放在指定区域上时,光标变为手,但图像不会翻转。因此,它识别定义的区域(带有坐标创建的多边形),但它不会翻转。Imageflip JavaScript不翻转
<html>
<head>
</head>
<body>
<img name="juego_paramo" src=paramo_plantas_original.gif usemap="#paramo">
<map name="paramo">
<area shape="poly" coords="0,161,4,161,4,162,12,162,12,163,19,163,26,165,34,166,45,168,52,170,62,174,73,177,82,180,91,184,103,188,112,192,122,196,133,202,142,207,152,212,162,216,172,221,180,224,186,227,193,230,197,233,0,233,0,161"
href="#" alt="helecho", onMouseOver="resaltarHelecho", onMouseOut="originalJuego">
<area shape="default" nohref>
</map>
<script>
//preload the images
original = new Image(698,233)
originale.src = "paramo_plantas_original.gif"
helechoResaltado = new Image(698,233)
helecho.src ="paramo_plantas_con_mouse_blanco.gif"
//JS function to enlarge the image
function resaltarHelecho() {
document.juego_paramo.src=helechoResaltado;
return true;
}
function originalJuego() {
document.juego_paramo.src=original;
return true;
}
</script>
</body>
</html>
我找不到错误。 任何提示在哪里寻找它?
脚注:在HTML中的onMouseOver应该全部小写:'onmouseover' – myfunkyside 2014-10-03 18:38:14
@myfunkyside很好的知道,但这并没有诀窍... – Maccaroni 2014-10-03 18:46:30
它应该看起来像这样? http://jsfiddle.net/matthias_h/wfyw63c4/ – 2014-10-03 18:49:51