2013-11-03 54 views
5

是否有可能使用Python“轰隆”我的无线Xbox 360控制器用于PC?我只找到了阅读输入的解决方案,但我找不到有关振动/隆隆声的信息。是否有可能使用Python“轰隆”Xbox 360控制器?

编辑:

继@AdamRosenfield提供我碰到下面的错误代码。

Traceback (most recent call last): 
    File "C:\Users\Usuario\Desktop\rumble.py", line 8, in <module> 
    xinput = ctypes.windll.Xinput # Load Xinput.dll 
    File "C:\Python27\lib\ctypes\__init__.py", line 435, in __getattr__ 
    dll = self._dlltype(name) 
    File "C:\Python27\lib\ctypes\__init__.py", line 365, in __init__ 
    self._handle = _dlopen(self._name, mode) 
WindowsError: [Error 126] The specified module could not be found. 

请注意,最后一个错误是从西班牙文翻译过来的。

回答

4

这是可能的,但并不容易。在C中,你会使用XInputSetState() function来控制隆隆声。要从Python访问它,你必须编译用C编写的Python扩展或使用ctypes library

像这样的事情应该工作,但要记住我没有测试过这一点:

import ctypes 

# Define necessary structures 
class XINPUT_VIBRATION(ctypes.Structure): 
    _fields_ = [("wLeftMotorSpeed", ctypes.c_ushort), 
       ("wRightMotorSpeed", ctypes.c_ushort)] 

xinput = ctypes.windll.xinput1_1 # Load Xinput.dll 

# Set up function argument types and return type 
XInputSetState = xinput.XInputSetState 
XInputSetState.argtypes = [ctypes.c_uint, ctypes.POINTER(XINPUT_VIBRATION)] 
XInputSetState.restype = ctypes.c_uint 

# Now we're ready to call it. Set left motor to 100%, right motor to 50% 
# for controller 0 
vibration = XINPUT_VIBRATION(65535, 32768) 
XInputSetState(0, ctypes.byref(vibration)) 

# You can also create a helper function like this: 
def set_vibration(controller, left_motor, right_motor): 
    vibration = XINPUT_VIBRATION(int(left_motor * 65535), int(right_motor * 65535)) 
    XInputSetState(controller, ctypes.byref(vibration)) 

# ... and use it like so 
set_vibration(0, 1.0, 0.5) 
+0

谢谢回答,我收到提示与“ctypes.struct”:这不是一个有效的属性。我也不知道“ctypes.struct”来自哪里! – Belohlavek

+0

@Belohlavek:哎呀,应该是'Structure',而不是'struct'。 –

+0

周末好项目! +1 –

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