2017-12-02 62 views
0

试图找出填充此表最后一列的最快方法,streak列存储运行结果值(winloss)。postgres:SQL和条纹?

game_date | team | result | streak 
------------+---------+--------+-------- 
2017-10-05 | ABC  | win | 1 
2017-10-07 | ABC  | win | 2 
2017-10-11 | ABC  | loss | 1 
2017-10-14 | ABC  | win | 1 
2017-10-15 | ABC  | win | 2 
2017-10-18 | ABC  | win | 3 
2017-10-21 | ABC  | win | 4 
2017-10-23 | ABC  | loss | 1 
2017-10-24 | ABC  | win | 1 
2017-10-26 | ABC  | win | 2 
2017-10-28 | ABC  | win | 3 
2017-10-30 | ABC  | loss | 1 
2017-11-02 | ABC  | win | 1 
2017-11-04 | ABC  | loss | 1 
2017-11-07 | ABC  | win | 1 
2017-11-09 | ABC  | loss | 1 
2017-11-12 | ABC  | loss | 1 
2017-11-14 | ABC  | loss | 2 
2017-11-16 | ABC  | loss | 3 
2017-11-18 | ABC  | win | 1 
2017-11-19 | ABC  | loss | 1 
2017-11-22 | ABC  | loss | 2 
2017-11-24 | ABC  | loss | 3 
2017-11-25 | ABC  | win | 1 
2017-11-28 | ABC  | win | 2 
2017-11-30 | ABC  | win | 3 
2017-12-01 | ABC  | win | 4 
(27 rows) 

正如你看到的,streak应该重置为1时,先结果为空,或者不同的,否则一个递增。

回答

0

您可以通过使用row_numbers()的区别来识别结果值的“孤岛”,从而识别获胜和丢失的序列。其余仅仅是最终的应用row_number()

select g.*, 
     row_number() over (partition by seqnum - seqnum_r, result order by game_date) as streak 
from (select g.*, 
      row_number() over (order by game_date) as seqnum, 
      row_number() over (partition by result order by game_date) as seqnum_r 
     from games g 
    ) g