基于索引列表求和列表元素

Question

我怎样才能得到结果和abResult？请引导我通过，我真的很感激它！

x=[1,2]  

y=[3,4,5] 

result= [3,9] <=== the sum of result determine by x 

============= OR ==========

a=[1,3,2] 

b= [4,2,3,4,5,10] 

abResult= [4,9,15] 

Answer 1

a=[1,3,2] 

b= [4,2,3,4,5,10] 

res=[] 

for i in a: 
    res.append(sum(b[:i])) 
    b=b[i:] 

资源存储您的结果

Answer 2

这是可能工作正常。

def isValid(counter, array): # valid if sum of counter equals array length 
    return sum(counter) == len(array) 

def calc(counter, array): 
    if not isValid(counter, array): 
     return [] 
    flag = 0 
    for x in counter: 
     yield sum(array[flag:flag+x]) # sum between (flag ~ flag+x) 
     flag += x      # add x to flag for next flag