-1
在Joomla 2.5上使用Mysql。 这是我的代码。很好的工作,除非没有用户(u)附加到团队(t)的结果。左连接组Concat
$query = "SELECT DISTINCT(t.id) as id,t.*, GROUP_CONCAT(DISTINCT ' ',MID(u.first_name,1,1) ,'.',u.last_name) as name
FROM #__bl_teams as t
LEFT JOIN (#__bl_teamcord as tc, #__users as u) ON(FIND_IN_SET(t.id,tc.teams)AND tc.u_id = u.id)
WHERE
t.id != 0
AND t.id != 1
AND ".$season_id." = t.s_id
GROUP BY t.id
ORDER BY t.t_name";
$db->setQuery($query);
$rows = $db->loadObjectList();
foreach($rows as $row){
echo $row->id.' - '.$row->name.'<br />';
}
我正在积极检查此页面,如果您有任何疑问...... – user1071915