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我正在构建一个Java Swing记忆游戏。这个想法是点击第一张牌,它将图像从baseImage更改为另一张图像。当点击第二张卡片时,它应该做同样的事情,等待几秒钟,然后如果它们不匹配,则将所有事件重置回基地,或者如果它们一起翻转,则将它们重置为基地。为什么我的第一个CardClicked.setDisabledIcon(img)能够工作,但我的第二个CardClicked.setDisabledIcon(img)不起作用?
现在,如果它们不匹配,第二张卡永不改变图像。以下是相关的代码。应该指出的是,如果他们确实匹配,那么图像就会显示出来,并且在世界上都是正确的。
public void cardClickHandler(ActionEvent ae) {
JButton card = new JButton();
card = (JButton) ae.getSource();
// disable the card that was clicked
card.setEnabled(false);
// behavior for first card clicked
if (clickCounter == 0) {
firstCardClicked = card;
img = new ImageIcon("images2/img" + firstCardClicked.getName() + ".jpg");
firstCardClicked.setDisabledIcon(img);
System.out.println("Button " + firstCardClicked.getName() + " clicked!");
clickCounter++;
}
// behavior for second card clicked
else {
secondCardClicked = card;
img = new ImageIcon("images2/img" + secondCardClicked.getName() + ".jpg");
secondCardClicked.setDisabledIcon(img);
System.out.println("Button " + secondCardClicked.getName() + " clicked!");
clickCounter--;
}
// behavior if two cards have been clicked and they match
if (firstCardClicked.getName().equals(secondCardClicked.getName()) && clickCounter == 0) {
// player turn control and scoring
if (p1Turn) {
p1NumScore++;
p1Score.setText(Integer.toString(p1NumScore));
scorePanel.revalidate();
System.out.println("Good job Mike, got a pair!");
p1Turn = !p1Turn;
}
else {
p2NumScore++;
p2Score.setText(Integer.toString(p2NumScore));
scorePanel.revalidate();
System.out.println("Good job Peanut, got a pair!");
p1Turn = !p1Turn;
}
}
// behavior if two cards have been clicked and they do not match
else if (!(firstCardClicked.getName().equals(secondCardClicked.getName())) && clickCounter == 0) {
// keep cards flipped for a few seconds
try {
System.out.println("Before Sleep"); // testing
Thread.sleep(2000);
System.out.println("After Sleep"); // testing
}
catch (Exception e) {
e.printStackTrace();
}
// enable the cards and reset images
firstCardClicked.setEnabled(true);
firstCardClicked.setIcon(baseImage);
secondCardClicked.setEnabled(true);
secondCardClicked.setIcon(baseImage);
// change turns
p1Turn = !p1Turn;
System.out.println("Keep Playing");
}
}
不要在事件处理中使用'Thread.sleep(int)'。它阻止了GUI。 –
请同时提供一个可运行的简短示例([MVCE](http://stackoverflow.com/help/mcve))。 –
@SergiyMedvynskyy作为一个初学者,我试图远离'Thread.sleep(int)',因为它与Swing有关的问题。不幸的是,我无法想出正确实现Swing Timer的方法,并且它运行得很好。我会尽力在明天把这个分解成MVCE。欣赏一切。 –