为什么不是第二个功能工作？

Question

我想做一个小游戏，但我没有很多经验。此外，我知道这可能是绝对不能做的最好办法，因此，如果任何人有什么适合初学者那简直太好了

<a id="key">There is a key on the floor</a> 
<button onclick="keylol()">Pick it up</button> 

<a id="door">You see a locked door</a> 
<button onclick="doortext()">Try to open the door</button> 

<script> 
var key = 1 
function keylol() { 
document.getElementById("key").innerHTML = "You picked up the key"; 
var key = 2; 
} 

function doortext() { 
if (key = 1) { 
document.getElementById("door").innerHTML = "You cannot open a locked door"; 
} else { 
document.getElementById("door").innerHTML = "You opened the door hooray"; 
} 
} 
</script> 

Answer 1

您需要使用===而非=：

if (key === 1) { 
    ... 
} 

Answer 2

你让两个错误：

第一个是，你重新声明一个在keylol功能的范围内命名key新的变量，因此价值2不是屁股与外部变量key对齐。

第二个是，您将重新声明key变量，而不是在if子句中比较它。

变化var key = 2到key = 2和if(key = 1)到if(key === 1)：

var key = 1 
 

 
function keylol() { 
 
    document.getElementById("key").innerHTML = "You picked up the key"; 
 
    key = 2; 
 
} 
 

 
function doortext() { 
 
    if (key === 1) { 
 
    document.getElementById("door").innerHTML = "You cannot open a locked door"; 
 
    } else { 
 
    document.getElementById("door").innerHTML = "You opened the door hooray"; 
 
    } 
 
}

<a id="key">There is a key on the floor</a> 
 
<button onclick="keylol()">Pick it up</button> 
 

 
<a id="door">You see a locked door</a> 
 
<button onclick="doortext()">Try to open the door</button>

Answer 3

<a id="key">There is a key on the floor</a> 
 
<button onclick="keylol()">Pick it up</button> 
 

 
<a id="door">You see a locked door</a> 
 
<button onclick="doortext()">Try to open the door</button> 
 

 
<script> 
 
var key = 1 
 
function keylol() { 
 
document.getElementById("key").innerHTML = "You picked up the key"; 
 
key = 2; 
 
} 
 

 
function doortext() { 
 
if (key == 1) { 
 
document.getElementById("door").innerHTML = "You cannot open a locked door"; 
 
} else { 
 
document.getElementById("door").innerHTML = "You opened the door hooray"; 
 
} 
 
} 
 
</script>