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加入django的mysqllite表对我来说是新的。我可以在一张桌子上查询得很好。并通过刚刚加入的mysql进行连接。我需要的是如何编写到表一起即模型和我的项目第一qustion是找出所有在大西洋confrence队加入两个表django新手问答
我 有鉴于此下面的例子
"atlanticsoccer": League.objects.filter(name__contains="atlantic")
this in html
<h5>Question 1</h5>
{% for whatever in atlanticsoccer %}
<li>{{whatever.name}}</li>
<li></li>
{% endfor %}
</ol>
which gives me all my Atlantic conference leauges. But i can't seem to find an example of how to join the teams by id . I have linked below the models view If i can get an example of how to do the first I can figure out the html. Thanks in advance for helping a new coder.
Models.py
from django.db import models
class League(models.Model):
name = models.CharField(max_length=50)
sport = models.CharField(max_length=15)
created_at = models.DateTimeField(auto_now_add=True)
updated_at = models.DateTimeField(auto_now=True)
class Team(models.Model):
location = models.CharField(max_length=50)
team_name = models.CharField(max_length=50)
league = models.ForeignKey(League, related_name="teams")
class Player(models.Model):
first_name = models.CharField(max_length=15)
last_name = models.CharField(max_length=15)
curr_team = models.ForeignKey(Team, related_name="curr_players")
all_teams = models.ManyToManyField(Team, related_name="all_players")
views.py
from django.shortcuts import render, redirect
from .models import League, Team, Player
from . import team_maker
def index(request):
context = {
"leagues": League.objects.all(),
"teams": Team.objects.all(),
"players": Player.objects.all(),
"atlanticsoccer": League.objects.filter(name__contains="atlantic")
}
return render(request, "leagues/index.html", context)
def make_data(request):
team_maker.gen_leagues(10)
team_maker.gen_teams(50)
team_maker.gen_players(200)
return redirect("index")
index.html
<h5>Question 1</h5>
{% for whatever in atlanticsoccer %}
<li>{{whatever.name}}</li>
<li></li>
{% endfor %}
</ol>
Ty是我正在寻找的例子,现在我可以完成剩下的工作。 –
去我的朋友的路。快乐的编码! –
如果你仍然在那里是的,这拉我所需要的所有数据是否有一个技巧,只是从一个certian体育和联赛拉队? –