我有一个表格显示表格中每个工程师的复选框。如果工程师的复选框未勾选,表单将被提交,它们将从作业中删除($ diary_id)。in_array()期望参数2是数组,空给出的错误
此时的代码正常工作,但在返回下一页之前,页面会简要显示此错误。
in_array()预计参数2为阵列,空给定的错误
表格中的代码...
$sql = "SELECT * FROM users WHERE type = 'engineer' ORDER BY first_name";
$result = mysql_query($sql) or die(mysql_error());
while ($row = mysql_fetch_array($result)){ ?>
<div style="width:70px; float:left">
<input type="hidden" name="engineer_on_page[]" value="<? echo $row['id']; ?>"/>
<input type="checkbox" name="engineer[]" <?
$eng_id= $row['id'];
$result2 = mysql_query("SELECT * FROM calls_engineers WHERE call_ce = '$diary_id' AND engineer_ce = '$eng_id'");
if((mysql_num_rows($result2)) > 0)
{ echo 'checked="checked"';
?> value="<? echo $row['id']; ?>" />
<? echo ' '.$row['first_name']; }
else {
echo "value=".$row['id']." />";
echo ' '.$row['first_name'];
}
?>
</div>
<? } ?>
MySQL的去除未被选择的工程师
foreach($_POST['engineer_on_page'] as $engineer_id) {
$sql = "SELECT * FROM calls_engineers WHERE call_ce = '$diary_id' AND engineer_ce = '$engineer_id'";
$result = mysql_query($sql)or die(mysql_error());
if(!in_array($engineer_id, $_POST['engineer'])){
if(mysql_num_rows($result) > 0){
$sql = "DELETE FROM calls_engineers WHERE engineer_ce = '$engineer_id' AND call_ce = '$diary_id'";
$result = mysql_query($sql)or die(mysql_error());
}
}
}
我试图在foreach循环之前初始化$ _POST ['engineer']作为数组($ _POST ['engineer'] = array();),但它也停止了页面的工作,没有错误消息,它只是不再工作。
我知道这个页面需要更新到mysqli,但我想在这之前先解决这个问题。
感谢
更换'如果(!in_array($ engineer_id,$ _ POST [ '工程师'])){'和'如果(isset($ _ POST [ '工程师'])&& is_array($ _ POST [ '工程师'])&& !in_array($ engineer_id,$ _POST ['engineer'])){' – Ejaz 2013-05-02 20:54:23
@Ejay,谢谢你,但它停止工作页面 – tatty27 2013-05-02 21:02:04
'停止页面工作'你的意思是你得到一些错误?或者它不执行删除语句? – Ejaz 2013-05-02 21:13:05