MySQL交叉表/数据透视聚合。删除基于列数其他表

我有以下格式的一组数据：

CAR_INVENTORY TABLE 
CAR_ID MAKE_MODEL  COLOR YEAR 
1  Ford Fusion  Black 2015 
2  Tesla Model S White 2014 
3  Acura ILX  Blue 2013 
4  Ford Fusion  Black 2013 
5  Toyota Corolla Blue 2014 
6  Ford Fusion  Blue 2013 
7  Toyota Corolla Blue 2012 
8  Acura ILX  Black 2015 
9  Ford Focus  Blue 2012 
10  Ford Fusion  White 2013 
11  Acura ILX  Black 2012 
12  Toyota Corolla Black 2015 
13  Toyota Corolla Blue 2014 
14  Ford Focus  White 2015 
15  Tesla Model S Red  2015 
16  Acura TLX  White 2014 
17  Toyota Corolla Blue 2014 
18  Ford Focus  Black 2013 

INVENTORY_LOG TABLE 
LOG_ID CAR_ID NOTE 
1  7  Issue with Fuel Guage 
2  3  Sweet Ride 
3  16  Zippy 
4  14  Issue with transmission 
5  3  Fun to Drive 
6  2  *NULL* 
7  8  *NULL* 
8  10  Economic 
9  15  WOW 
10  9  Good Fuel Economy 
11  16  Minor issue with Shifting 
12  7  Issue with Airbag 
13  17  Great Mileage 
14  1  Nice Tech 
15  13  *NULL* 
16  11  Trunk is small 
17  12  *NULL* 
18  2  Very Speedy 
19  7  Good Mileage 
20  10  Roomy 
21  4  *NULL* 
22  6  Nice Tech Package 
23  5  Good Economy 
24  18  Cool

我知道这不是完全正常化。我们假设我不能搞乱数据。

car_inventory表中每辆车都有一排库存。 inventory_log表对于car_inventory中列出的每辆车至少有一个条目，因此每辆车可能有许多日志条目。 inventory_log中的条目可以为null。

我到目前为止

如果汽车有它的词“问题”日志完成，它需要进行标注。我已经想通的那部分：

SELECT 
    ci.car_id, 
    CONCAT(ci.color, " ", ci.make_model) as car, 
    SUM(IF (LOWER(il.note) LIKE '%issue%', TRUE, FALSE)) AS issue 
FROM car_inventory ci 
    LEFT JOIN inventory_log il USING (car_id) 
GROUP BY ci.car_id 
ORDER BY ci.car_id;

这yealds：

car_id car      issue 
1  Black Ford Fusion  0 
2  White Tesla Model S  0 
3  Blue Acura ILX   0 
4  Black Ford Fusion  0 
5  Blue Toyota Corolla  0 
6  Blue Ford Fusion  0 
7  Blue Toyota Corolla  2 
8  Black Acura ILX   0 
9  Blue Ford Focus   0 
10  White Ford Fusion  0 
11  Black Acura ILX   0 
12  Black Toyota Corolla 0 
13  Blue Toyota Corolla  0 
14  White Ford Focus  1 
15  Red Tesla Model S  0 
16  White Acura TLX   1 
17  Blue Toyota Corolla  0 
18  Black Ford Focus  0

这给非零结果与问题的任何汽车。

我需要做的下一件事是通过他们的颜色，超过一定的年份计数所有。假设我们只对黑色，白色和蓝色感兴趣，我们只有福特，讴歌，丰田和特斯拉（我知道我可以使用准备好的语句来实现这种动态）。明白了一个中袋过：

SELECT 
    CASE 
     WHEN ci.make_model LIKE "Acura%" THEN "Acura" 
     WHEN ci.make_model LIKE "Ford%" THEN "Ford" 
     WHEN ci.make_model LIKE "Toyota%" THEN "Toyota" 
     WHEN ci.make_model LIKE "Tesla%" THEN "Tesla" 
    END AS Make, 
    SUM(CASE WHEN ci.color = "Black" THEN 1 ELSE 0 END) as Black, 
    SUM(CASE WHEN ci.color = "Blue" THEN 1 ELSE 0 END) as Blue, 
    SUM(CASE WHEN ci.color = "White" THEN 1 ELSE 0 END) as White 
FROM car_inventory ci 
    LEFT JOIN inventory_log il USING (car_id) 
WHERE 
    ci.year > 2012 
GROUP BY Make 
ORDER BY Make;

这给了我：

Make Black Blue White 
Acura 1  1  1 
Ford 3  1  2 
Tesla 0  0  1 
Toyota 1  3  0

在做car_inventory表的快速计数，有14辆汽车于2012年更新的，那是黑色，蓝色或白色。

的问题

这里就是我有麻烦：

我试图做的是将二者结合起来。我需要根据颜色来计算所有颜色，哪里没有问题。

这里的结果集，我试图让：

DESIRED RESULT 
MAKE   Black Blue White 
Acura   1  1  0 
Ford   3  1  1 
Tesla   0  0  1 
Toyota   1  2  0

以下三个车中删除：

car_id car      issues 
7  Blue Toyota Corolla  2 
14  White Ford Focus  1 
16  White Acura TLX   1

我尝试添加AND SUM(IF (LOWER(il.note) LIKE '%issue%', TRUE, FALSE)) = 0 WHERE子句。这会导致mysql错误1111“组功能的无效使用”。我也试过HAVING SUM(IF (LOWER(il.note) LIKE '%issue%', TRUE, FALSE)) != 0。它不正确的结果，只显示特斯拉和丰田的行。

问题

如何创建MySQL中的交叉表查询，使得汽车（从car_inventory）与在他们所说的“问题”的日志条目（来自inventory_log）不计？

来源

2016-05-03 mcmurphy

SELECT 
    CASE 
     WHEN ci.make_model LIKE "Acura%" THEN "Acura" 
     WHEN ci.make_model LIKE "Ford%" THEN "Ford" 
     WHEN ci.make_model LIKE "Toyota%" THEN "Toyota" 
     WHEN ci.make_model LIKE "Tesla%" THEN "Tesla" 
    END AS Make, 
    SUM(CASE WHEN ci.color = "Black" THEN 1 ELSE 0 END) as Black, 
    SUM(CASE WHEN ci.color = "Blue" THEN 1 ELSE 0 END) as Blue, 
    SUM(CASE WHEN ci.color = "White" THEN 1 ELSE 0 END) as White 
FROM car_inventory ci 
WHERE 
    (ci.year > 2012) and 
    (ci.car_id not in (select distinct il.car_id from inventory_log il where il.note like '%issue%')) 
GROUP BY Make 
ORDER BY Make;

来源

2016-05-05 21:04:04 Dave

将子查询移动到where子句似乎更快。谢谢。 – mcmurphy

所以我想出如何使用子查询做到这一点：

SELECT 
    CASE 
     WHEN ci.make_model LIKE "Acura%" THEN "Acura" 
     WHEN ci.make_model LIKE "Ford%" THEN "Ford" 
     WHEN ci.make_model LIKE "Toyota%" THEN "Toyota" 
     WHEN ci.make_model LIKE "Tesla%" THEN "Tesla" 
    END AS Make, 
    SUM(CASE WHEN ci.color = "Black" THEN 1 ELSE 0 END) as Black, 
    SUM(CASE WHEN ci.color = "Blue" THEN 1 ELSE 0 END) as Blue, 
    SUM(CASE WHEN ci.color = "White" THEN 1 ELSE 0 END) as White 
FROM (

     SELECT 
      ci2.car_id, 
      ci2.make_model, 
      ci2.color 
     FROM car_inventory ci2 
      LEFT JOIN inventory_log il2 USING (car_id) 
     WHERE 
      ci2.year > 2012 
     GROUP BY ci2.car_id 
     HAVING SUM(IF (LOWER(il2.note) LIKE '%issue%', TRUE, FALSE)) = 0 

) as ci 
GROUP BY Make 
ORDER BY Make;

这给了我：

Make Black Blue White 
Acura 1  1  0 
Ford 3  1  1 
Tesla 0  0  1 
Toyota 1  3  0

我不会将此标记为接受的答案，因为我很确定没有子查询有更好，更高效的方法来做到这一点。

来源

2016-05-04 16:53:23 mcmurphy

MySQL交叉表/数据透视聚合。删除基于列数其他表

回答

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