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选择车名我有下面的XML文件：XSLT - 用户

<?xml version="1.0" encoding="utf-8" ?> 
<?xml-stylesheet version="1.0" type="text/xml" href="template.xsl" ?> 
<source> 
    <man name="John" surname="Piterson" > 
     <cars> 
      <car name="Lamborgini Gallardo" maxspeed="400km" /> 
      <car name="Honda" maxspeed="200km" /> 
     </cars> 
     <appartments> 
      <appartment city="New York" /> 
      <appartment city="Tokio" /> 
     </appartments> 
    </man> 
</source>

，我有以下的XSL模板，它应该显示汽车的名单

<?xml version="1.0" encoding="utf-8"?> 
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > 
    <xsl:template match="/" > 
     <html> 
      <body> 
       <h1>Users info</h1> 
       <div><strong>The cars of John</strong></div> 
       <xsl:for-each select="/man/cars/car" > 
        <div> 
         <xsl:value-of select="[email protected]" /> 
        </div> 
       </xsl:for-each> 
      </body> 
     </html> 
    </xsl:template> 
</xsl:stylesheet>

我需要打印所有汽车约翰的名字，<xsl:for-each - 在这种情况下不起作用，该怎么做？

来源

2012-09-07 testCoder

<xsl:for-each select="/source/man[@name='John'][@surname='Piterson']/cars/car" > 
    <div> 
    <xsl:value-of select="@name" /> 
    </div> 
</xsl:for-each>

来源

2012-09-07 06:41:03

是的，它的工作，谢谢！ – testCoder

<xsl:for-each select="//man[@name = 'John']" > 
    <ul> 
    <xsl:for-each select="./cars/car" > 
     <li> 
     <xsl:value-of select="@name"/>: <xsl:value-of select="@maxspeed"/> 
     </li> 
    </xsl:for-each> 
    </ul> 
</xsl:for-each>

来源

2012-09-07 06:52:07

XSLT - 用户

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