1
我想在HTML表中填充数据库结果。单击<a class="editUsers">
时,应弹出一个框以显示来自Ajax调用的数据。使用JQuery,Ajax和PHP将数据填充到表中
这应该被示出:
<table id="userInfo">
<tr>
<thead>
<td>User</td>
<td>Mail</td>
<td>Admin Access</td>
</thead>
</tr>
<tr>
<td>Jane Doe</td>
<td>[email protected]</td>
<td>Yes</td>
</tr>
</table>
$(".editUsers").click(function(){
$("#userInfo").fadeIn(1000);
$(".exitUsrMgmt").fadeIn(1000); //This is the close button for that popup
$.ajax({ //create an ajax request to load_page.php
type: "GET",
url: "includes/getUserData.php",
dataType: "html", //expect html to be returned
success: function(response){
("#userInfo").html(response);
},
error:function (xhr, ajaxOptions, thrownError){
alert(thrownError);
}
});
});
<?php
include_once('config.php');
//Create PDO Object
$con = new PDO(DB_DSN, DB_USERNAME, DB_PASSWORD);
//Set Error Handling for PDO
$con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
//Query
$sql = "SELECT name, email, admin FROM user_admin";
//Prepare Statement
$stmt = $con->prepare($sql);
$stmt->execute();
while ($row = $stmt->fetch()){
echo '<tr>';
echo '<td>'.$row[0].'</td>';
echo '<td>'.$row[1].'</td>';
echo '<td>'.$row[2].'</td>';
echo '</tr>';
}
?>
对于初学者,'(“#userInfo”)。html(response);'缺少'$'。应该是'$(“#userInfo”)。html(response);' –
哇。我现在可以用砖块打自己。我看了30分钟的代码,并没有发现这个愚蠢的错误。现在一切正常。谢谢:) – nTuply
这可以帮助你:http://stackoverflow.com/questions/30770664/jquery-click-not-working-on-appended-tr-from-ajax/30771297#30771297 –