用Python和matplotlib连接三维散点图中的两点

Question

在下面的代码中，如何创建由两行代码创建的连接每对散点图的线（即将绿色圆圈连接到黄色箭头） .show（）指令之前的结束？

import matplotlib.pyplot 
from mpl_toolkits.mplot3d import Axes3D 

dates  = [20020514, 20020515, 20020516, 20020517, 20020520] 
highs  = [1135, 1158, 1152, 1158, 1163] 
lows  = [1257, 1253, 1259, 1264, 1252] 
upperLimits = [1125.0, 1125.0, 1093.75, 1125.0, 1125.0] 
lowerLimits = [1250.0, 1250.0, 1156.25, 1250.0, 1250.0] 

zaxisvalues0= [0, 0, 0, 0, 0] 
zaxisvalues1= [1, 1, 1, 1, 1] 
zaxisvalues2= [2, 2, 2, 2, 2] 

fig = matplotlib.pyplot.figure() 
ax = fig.add_subplot(111, projection = '3d') 

ax.plot(dates, zaxisvalues1, lowerLimits, color = 'b') 
ax.plot(dates, zaxisvalues2, upperLimits, color = 'r') 

ax.scatter(dates, zaxisvalues0, highs, color = 'g', marker = "o") 
ax.scatter(dates, zaxisvalues0, lows, color = 'y', marker = "^") 

matplotlib.pyplot.show() 

Answer 1

画一条线段的点之间：

import matplotlib.pyplot 
from mpl_toolkits.mplot3d import Axes3D 

dates  = [20020514, 20020515, 20020516, 20020517, 20020520] 
highs  = [1135, 1158, 1152, 1158, 1163] 
lows  = [1257, 1253, 1259, 1264, 1252] 
upperLimits = [1125.0, 1125.0, 1093.75, 1125.0, 1125.0] 
lowerLimits = [1250.0, 1250.0, 1156.25, 1250.0, 1250.0] 

zaxisvalues0= [0, 0, 0, 0, 0] 
zaxisvalues1= [1, 1, 1, 1, 1] 
zaxisvalues2= [2, 2, 2, 2, 2] 

fig = matplotlib.pyplot.figure() 
ax = fig.add_subplot(111, projection = '3d') 

ax.plot(dates, zaxisvalues1, lowerLimits, color = 'b') 
ax.plot(dates, zaxisvalues2, upperLimits, color = 'r') 

for i,j,k,h in zip(dates,zaxisvalues0,lows,highs): 
    ax.plot([i,i],[j,j],[k,h],color = 'g') 

ax.scatter(dates, zaxisvalues0, highs, color = 'g', marker = "o") 
ax.scatter(dates, zaxisvalues0, lows, color = 'y', marker = "^") 

matplotlib.pyplot.show() 

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