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下面是一张图片，说明我正在尝试做什么。找到旋转后的图像内的原始点c＃
我旋转在c＃的图像（白色矩形）。 问题是我需要将绿色正方形（另一个图像）放在与矩形相同的点上，而不管旋转。绿色正方形不能与矩形一起旋转。
正如你可以看到在白色矩形旋转后，我每次都会得到不同大小的画布。
我想找到确切的点来放置新的旋转图像创建后的绿色广场。
以下OK是一些代码，它旋转图像并将点放在正确的位置。 现在的问题是，如果我在RotateImage方法中应用转换，我会看到所有的rectagle，但显然我的红点在错误的位置。 我应该强调，我需要知道点的位置，而不是将它放在正确的位置。
public class IconController : Controller
{
//
// GET: /Icon/
public ActionResult Index()
{
return View();
}
////Icon/Icon?connected=true&heading=320&type=logo45
public ActionResult Icon(bool connected, float heading, string type)
{
var dir = Server.MapPath("/images");
//RED SQUARE IM TRYING TO PLACE ON THE BLUE RECTANGLE.
var path = Path.Combine(dir, "mapicons/center.png");
//GREEN RECTANGLE WITH FIXED YELLOW (Actual center) AND BLUE (point im really trying to find)
var path2 = Path.Combine(dir, "mapicons/connected-marker.png");
Image innerIcon = Image.FromFile(path);
Image marker = Image.FromFile(path2);
using (marker)
{
Point orginalCenter = new Point((marker.Width/2), (marker.Height/2));
Bitmap markerbitmap = RotateImage(new Bitmap(marker), heading);
marker = (Image)markerbitmap;
using (var bitmap = new Bitmap(marker.Width, marker.Height))
{
using (var canvas = Graphics.FromImage(bitmap))
{
PointF newCenter = RotatePoint(orginalCenter, 80, 120, heading, marker.Width, marker.Height);
canvas.DrawRectangle(new Pen(Color.Black), 0, 0, bitmap.Width, bitmap.Height);
canvas.InterpolationMode = InterpolationMode.HighQualityBicubic;
canvas.DrawImage(marker, new Rectangle(0, 0, marker.Width, marker.Height), new Rectangle(0, 0, marker.Width, marker.Height), GraphicsUnit.Pixel);
canvas.DrawImage(innerIcon, newCenter.X - (innerIcon.Width/2), newCenter.Y - (innerIcon.Height/2));
canvas.Save();
}
try
{
bitmap.Save(Path.Combine(dir, "result.png"), ImageFormat.Png);
path = Path.Combine(dir, "result.png");
}
catch (Exception ex) { }
}
}
return base.File(path, "image/png");
}
public static Bitmap RotateImage(Bitmap b, float Angle)
{
// The original bitmap needs to be drawn onto a new bitmap which will probably be bigger
// because the corners of the original will move outside the original rectangle.
// An easy way (OK slightly 'brute force') is to calculate the new bounding box is to calculate the positions of the
// corners after rotation and get the difference between the maximum and minimum x and y coordinates.
float wOver2 = b.Width/2.0F;
float hOver2 = b.Height/2.0F;
float radians = -(float)(Angle/180.0 * Math.PI);
// Get the coordinates of the corners, taking the origin to be the centre of the bitmap.
PointF[] corners = new PointF[]{
new PointF(-wOver2, -hOver2),
new PointF(+wOver2, -hOver2),
new PointF(+wOver2, +hOver2),
new PointF(-wOver2, +hOver2)
};
for (int i = 0; i < 4; i++)
{
PointF p = corners[i];
PointF newP = new PointF((float)(p.X * Math.Cos(radians) - p.Y * Math.Sin(radians)), (float)(p.X * Math.Sin(radians) + p.Y * Math.Cos(radians)));
corners[i] = newP;
}
// Find the min and max x and y coordinates.
float minX = corners[0].X;
float maxX = minX;
float minY = corners[0].Y;
float maxY = minY;
for (int i = 1; i < 4; i++)
{
PointF p = corners[i];
minX = Math.Min(minX, p.X);
maxX = Math.Max(maxX, p.X);
minY = Math.Min(minY, p.Y);
maxY = Math.Max(maxY, p.Y);
}
// Get the size of the new bitmap.
SizeF newSize = new SizeF(maxX - minX, maxY - minY);
// ...and create it.
Bitmap returnBitmap = new Bitmap((int)Math.Ceiling(newSize.Width), (int)Math.Ceiling(newSize.Height));
// Now draw the old bitmap on it.
using (Graphics g = Graphics.FromImage(returnBitmap))
{
g.TranslateTransform(newSize.Width/2.0f, newSize.Height/2.0f);
g.RotateTransform(Angle);
g.TranslateTransform(-b.Width/2.0f, -b.Height/2.0f);
g.DrawImage(b, 0, 0);
}
return returnBitmap;
}
public static Point RotatePoint(Point pointToRotate, Point centerPoint, double angleInDegrees)
{
double angleInRadians = angleInDegrees * (Math.PI/180);
double cosTheta = Math.Cos(angleInRadians);
double sinTheta = Math.Sin(angleInRadians);
Point pt = new Point();
pt.X = (int)(cosTheta * (pointToRotate.X-centerPoint.X) - sinTheta * (pointToRotate.Y-centerPoint.Y) + centerPoint.X);
pt.Y = (int)(sinTheta * (pointToRotate.X - centerPoint.X) + cosTheta * (pointToRotate.Y - centerPoint.Y) + centerPoint.Y);
//p'y = sin(theta) * (px-ox) + cos(theta) * (py-oy) + oy
return pt;
}
}
所以现在我需要能够取消对TranslateTransform在RotateImage方法，让我看到了正确的矩形和修改RotatePoint方法，所以我得到正确的新位置
你需要做数学题，即旋转相匹配。也许谷歌“旋转矩形算法”。您正在寻找给定4个角的XY位置的数学，应用旋转。我强调你正在寻找MATH，而不是调用GUI。使用Sin（）和Cos（）的东西。那么你需要弄清楚这与你的视觉形象有何关系。 – ToolmakerSteve
OK上面确实打算。 @ToolmakerSteve谢谢你指点我正确的方向。不知道如何标记为答案等 – Ray
很高兴这有帮助。你可以为自己的问题写一个答案（“回答你的问题”按钮），并鼓励他们这样做，这样人们就知道它已经得到了回答。然后将其标记为答案。如果您在问题中已经更正了这个问题，那么您可能会在回答中显示“之前”和“之后”，以表明您最初失踪的内容。 – ToolmakerSteve