Python - 用PyRSS2Gen生成RSS

我正在尝试编写一个程序，该程序利用urllib2来解析HTML，然后利用PyRSS2Gen创建XML中的RSS源。Python - 用PyRSS2Gen生成RSS

我一直在试图运行它得到的错误

Traceback (most recent call last): File "pythonproject.py", line 46, in get_rss() File "pythonproject.py", line 43, in get_rss rss.write_xml(open("cssnews.rss.xml", "w")) File "build/lib/PyRSS2Gen.py", line 34, in write_xml self.publish(handler) File "build/lib/PyRSS2Gen.py", line 380, in publish item.publish(handler) File "build/lib/PyRSS2Gen.py", line 427, in publish _opt_element(handler, "title", self.title) File "build/lib/PyRSS2Gen.py", line 58, in _opt_element _element(handler, name, obj) File "build/lib/PyRSS2Gen.py", line 53, in _element obj.publish(handler) AttributeError: 'builtin_function_or_method' object has no attribute 'publish'

。

从我能找到的其他用户在尝试为XML创建新标记时遇到此问题，但我试图使用PyRSS2Gen给出的默认标记。检查PyRSS2Gen.py文件显示我正在使用的write_xml（）命令，以及如何通过从列表中弹出它们将值分配给rss项目的错误？

def get_rss(): 
    sys.path.append('build/lib') 
    from PyRSS2Gen import RSS2, RSSItem 

    rss = RSS2(
     title = 'Python RSS Creator', 
     link = 'technews.acm.org', 
     description = 'Creates RSS out of HTML', 
     items = [], 
    ) 

    for x in range(0, len(rssTitles)): 
     rss.items.append(RSSItem(
      title = rssTitles.pop, 
      link = rssLinks.pop, 
      description = rssDesc.pop, 
     )) 

    rss.write_xml(open("cssnews.rss.xml", "w")) 

# 5 - Call function 
get_rss()

来源

2016-03-30 rkanson

我最后只是写了一个文件，像这样;

news = open("news.rss.xml", "w") 
news.write("<?xml version=\"1.0\" ?>") 
news.write("\n") 
news.write("<rss xmlns:atom=\"http://www.w3.org/2005/Atom\" version=\"2.0\">") 
news.write("\n") 
news.write("<channel>") 
news.write("\n")

等

来源

2016-03-31 21:37:54 rkanson

Python - 用PyRSS2Gen生成RSS

回答

相关问题