我正在修改一个php登录表单,并在其中添加了javascript check form函数。我希望当用户勾选复选框时,表单为真,当复选框为空时,表单将变为false。代码是这样的: -复选框值在检查窗体中,php
//the javascript
function check_sli(form,mark,edit){
if(mark==1 || mark=="all"){
if(form.terms.value==""){
sli_check_terms.innerHTML="Please read the terms and conditions first!";
sli_check_terms.style.height="auto";
return false;
}else{
sli_check_terms.innerHTML="";
sli_check_terms.style.display = "none";
}
}
}
//the form
<form name="form_sli" id = "form_sli" ACTION="<?php echo $loginFormAction1; ?>" METHOD="POST" onSubmit="return check_sli(form_sli,'all')">
<input type="text" name="login"/><br>
<input type="password" name="password"/><br>
<input name="terms" type="checkbox" id="terms" checked="checked" onBlur="check_sli(form_sli,1)">I have read the terms and conditions<br><div id="sli_check_terms" class="right"></div>
<input type="submit" name="button" id="button" value="Login" />
</form>
上述代码的工作正常的文本框,诸如当文本字段是空的,的innerHTML弹出。但是,当使用复选框,我不知道检查和未检查的值,是1比0还是!==“”vs ==“”?并且我应该使用onBlur还是onSubmit?
它应该如何修改脚本以使其对复选框起作用?非常感谢!