我不想将缩放比例用作经典缩放比例,而是想将比例形式更改为矩形比如。 经过很多尝试,我到目前为止,我的手指是矩形的角落。 所以,但如果我在我的视图内开始一个新的捏手势让我的手指更小,而不是像正常的规模变大。UIPinchGestureRecognizer在不同的x和y方向上缩放视图
if ([gestureRecognizer numberOfTouches] >1) {
//getting width and height between gestureCenter and one of my finger
float x = [gestureRecognizer locationInView:self].x - [gestureRecognizer locationOfTouch:0 inView:self].x;
if (x<0) {
x *= -1;
}
float y = [gestureRecognizer locationInView:self].y - [gestureRecognizer locationOfTouch:0 inView:self].y;
if (y<0) {
y *= -1;
}
//double size cause x and y is just the way from the middle to my finger
float width = x*2;
if (width < 1) {
width = 1;
}
float height = y*2;
if (height < 1) {
height = 1;
}
self.bounds = CGRectMake(self.bounds.origin.x , self.bounds.origin.y , width, height);
[gestureRecognizer setScale:1];
[[self layer] setBorderWidth:2.f];
}
没有人知道一种方法来制作X-Y-Scale,它不会调整到我的手指位置作为角落。
非常感谢您
[在水平和垂直方向缩放UIPinchGestureRecognizer的单独(可能的重复https://stackoverflow.com/questions/12354959/scale-of-uipinchgesturerecognizer-in-horizontal-和垂直方向分开) – Fattie 2017-07-12 00:52:56
为什么这个问题是重复的,如果它比较老,甚至有可接受的答案? – Seega 2017-07-12 15:03:58