问题:通过以列表形式传入的分隔符将字符串拆分为单词列表。字符串拆分问题
字符串:"After the flood ... all the colors came out."
所需的输出:['After', 'the', 'flood', 'all', 'the', 'colors', 'came', 'out']
我写了下面的功能 - 注意,我知道有更好的方法使用一些内置的功能蟒蛇来分割字符串,但为求学习,我想我会继续这样说:
def split_string(source,splitlist):
result = []
for e in source:
if e in splitlist:
end = source.find(e)
result.append(source[0:end])
tmp = source[end+1:]
for f in tmp:
if f not in splitlist:
start = tmp.find(f)
break
source = tmp[start:]
return result
out = split_string("After the flood ... all the colors came out.", " .")
print out
['After', 'the', 'flood', 'all', 'the', 'colors', 'came out', '', '', '', '', '', '', '', '', '']
我想不通为什么“出笼”不拆分为“来”和“走出去”作为两个单独的单词。就好像两个单词之间的空白字符被忽略一样。我认为其余的产出是垃圾,这是源于与“出来”问题相关的问题。
编辑:
我跟着@ IVC的建议,并用下面的代码上来:
def split_string(source,splitlist):
result = []
lasti = -1
for i, e in enumerate(source):
if e in splitlist:
tmp = source[lasti+1:i]
if tmp not in splitlist:
result.append(tmp)
lasti = i
if e not in splitlist and i == len(source) - 1:
tmp = source[lasti+1:i+1]
result.append(tmp)
return result
out = split_string("This is a test-of the,string separation-code!"," ,!-")
print out
#>>> ['This', 'is', 'a', 'test', 'of', 'the', 'string', 'separation', 'code']
out = split_string("After the flood ... all the colors came out.", " .")
print out
#>>> ['After', 'the', 'flood', 'all', 'the', 'colors', 'came', 'out']
out = split_string("First Name,Last Name,Street Address,City,State,Zip Code",",")
print out
#>>>['First Name', 'Last Name', 'Street Address', 'City', 'State', 'Zip Code']
out = split_string(" After the flood ... all the colors came out...............", " ."
print out
#>>>['After', 'the', 'flood', 'all', 'the', 'colors', 'came', 'out']
谢谢大家的精彩解决方案。我已经走了这一条,因为它迫使我学习逻辑,而不是使用预先构建的函数。显然,如果我要写商业代码,我不会重新发明轮子,但为了学习的目的,我会与这个答案一起去。感谢大家的帮助。 – codingknob