传递参数给JSON邮政法无

Question

NSString *Str = @"Basic YnRwaXhlbDoxMjM0NQ=="; 
NSArray *keys = [NSArray arrayWithObjects: @"Authorization",nil]; 
NSArray *objects = [NSArray arrayWithObjects:Str,nil]; 
NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:objects forKeys:keys]; 
NSError * error = nil; 
NSData * jsonData = [NSJSONSerialization dataWithJSONObject:jsonDictionary options:NSJSONReadingMutableContainers error:&error]; 
NSURL *urlStr1 = [NSURL URLWithString:@"http://192.168.0.49/bubbletop/index.php?route=feed/rest_api/gettoken&grant_type=client_credentials"]; 

NSMutableURLRequest *request1 = [[NSMutableURLRequest alloc] initWithURL:urlStr1]; 
[request1 setHTTPMethod:@"POST"]; 
[request1 setValue:@"application/json" forHTTPHeaderField:@"Accept"]; 
[request1 setValue:@"application/json" forHTTPHeaderField:@"Content-Type"]; 
[request1 setValue:[NSString stringWithFormat:@"%lu", (unsigned long)[jsonData length]] forHTTPHeaderField:@"Content-Length"]; 
[request1 setHTTPBody: jsonData]; 
_connection = [[NSURLConnection alloc]initWithRequest:request1 delegate:self startImmediately:YES]; 


NSData *data1 = [NSData dataWithContentsOfURL:urlStr1]; 


NSDictionary *fashionJson = [NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:nil]; 
NSLog(@"requestReply: %@", fashionJson); 

在这里，我传递的报头字段参数作为Basic YnRwaXhlbDoxMjM0NQ==的关键Authorization，但得到的数据作为零和获取日志作为

requestReply：（空）

Answer 1

我想你加入头域错

不喜欢

NSString *Str = @"Basic YnRwaXhlbDoxMjM0NQ=="; 
NSArray *keys = [NSArray arrayWithObjects: @"Authorization",nil]; 
NSArray *objects = [NSArray arrayWithObjects:Str,nil]; 
NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:objects forKeys:keys]; 
NSError * error = nil; 
NSData * jsonData = [NSJSONSerialization dataWithJSONObject:jsonDictionary options:NSJSONReadingMutableContainers error:&error]; 

不喜欢的HTTP令牌认证

[request1 addValue:@"Basic YnRwaXhlbDoxMjM0NQ==" forHTTPHeaderField:@"Authorization"]; 

注意

在这里

[request1 setHTTPBody: jsonData]; 

样品申请无需追加身体看this

Answer 2

由于您使用的是NSData *data1 = [NSData dataWithContentsOfURL:urlStr1];方法，因此它不会将您的httpbody从您创建的url请求中取出。执行NSURLConnection委托方法或使用NSURLSession加载数据。由于NSURLConnection API已弃用，因此我会建议NSURLSession。