1
只需划分一个PNG图像的信道来表示具有不与每个other.Below共混纹理泼洒是表达什么我试图实现为简单代码的示例:webgl的着色器 - 分通道RGBA
uniform sampler2D my-alpha-png;
uniform sampler2D texture1;
uniform sampler2D texture2;
uniform sampler2D texture3;
vec4 alpha = texture2D(my-alpha-png, vUV).rgba;
vec4 tex0 = texture2D(texture1, vUV *10.0).rgba;
vec4 tex1 = texture2D(texture2, vUV *10.0).rgba;
vec4 tex2 = texture2D(texture3, vUV *10.0).rgba;
vec4 colornone = alpha.a; // i want this channel to be blank;
vec4 color1 = alpha.r; // this is texture1
vec4 color2 = alpha.g; // this is texture2
vec4 color3 = alpha.b; // this is texture3
gl_FragColor = // ????
我已经尝试了许多变化我只能设法让两个纹理沃金,但阿尔法总是以及下方的纹理图像阿尔法PNG:
我更感兴趣的是分裂渠道代表在输出上,只需要四个通道r,g,b,一个不需要计算黑白...
谢谢。