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使用以下命令:ffmpeg - 多次写入相同的帧?
ffmpeg -i test.mp4 -vf "select='not(mod(n,2000))',setpts=N/3/TB" -r 3 output.gif
我写1帧,每2000,在3FPS GIF文件。
但是,当我看到FFmpeg的输出也有一些是令人困惑:
speed=0.00997frame= 1 fps=0.7 q=-0.0 size= 1kB time=00:00:00.01
speed=0.00498frame= 1 fps=0.4 q=-0.0 size= 1kB time=00:00:00.01
speed=0.00332frame= 2 fps=0.6 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0847xframe= 2 fps=0.4 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0678xframe= 2 fps=0.4 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0565xframe= 2 fps=0.3 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0968xframe= 3 fps=0.4 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0847xframe= 3 fps=0.4 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0753xframe= 3 fps=0.3 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0678xframe= 4 fps=0.4 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0915xframe= 4 fps=0.3 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0839xframe= 4 fps=0.3 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0774xframe= 4 fps=0.3 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0954xframe= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.089x frame= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.0834xframe= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.0785xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
speed=0.093x frame= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
speed=0.0881xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
speed=0.0837xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
它看起来像每个被重建多次,目标帧。 我希望是这样的:
speed=0.00997frame= 1 fps=0.7 q=-0.0 size= 1kB time=00:00:00.01
speed=0.00332frame= 2 fps=0.6 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0968xframe= 3 fps=0.4 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0678xframe= 4 fps=0.4 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0954xframe= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.0785xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
我缺少的东西?
(这是从一个ffmpeg - multiple output with thumbnails随访)
好的,我明白了;所以它不会处理多个源帧来更新目标帧。谢谢! – Thomas