我想将vector<vector<double> >
转换为Mat
,因为我需要将自定义平滑过滤器应用于此值。OpenCV - 将矢量矢量转换为垫子
图像下面显示了正确的值
我尝试这样做。
std::vector<std::vector<double> > angles;
calculateAngles(angles);
Mat matAngles(angles.size(), angles.at(0).size(), CV_64FC1, angles.data());
但是,第一列中的值是错误转换的,值为2.12566e-314。
所得图像
我还试图直接就把值在Mat
。
void calculateAngles(cv::Mat& im, cv::Mat& angles, int blockSize, int(*f)(int x, int y), int(*g)(int x, int y)){
static int ySobel[3][3] = {{-1, 0, 1}, {-2, 0, 2}, {-1, 0, 1}};
static int xSobel[3][3] = {{-1, -2, -1}, {0, 0, 0}, {1, 2, 1}};
angles.create(cv::Size(im.cols/blockSize+1, im.rows/blockSize+1), CV_64FC1);
int nominator;
int denominator;
int GX, GY;
double angle;
for(int i = 1; i < im.cols; i += blockSize){
for(int j = 1; j < im.rows; j += blockSize){
nominator = 0;
denominator = 0;
for(int k = i; k < std::min(i + blockSize, im.cols-1); k++){
for(int l = j; l < std::min(j + blockSize, im.rows-1); l++){
GX = applyKernelAt(im, xSobel, k, l);
GY = applyKernelAt(im, ySobel, k, l);
nominator += f(GX, GY);
denominator += g(GX, GY);
}
}
angle = (PI + std::atan2(nominator, denominator))/2;
angles.at<double>((i-1)/blockSize, (j-1)/blockSize) = angle;
}
}
}
但是这些值在某个点后重复。
这是值是如何印刷
void drawLines(cv::Mat& src, cv::Mat& dst, cv::Mat& angles, int blockSize){
cv::Size size = src.size();
dst.create(src.size(), src.type());
// for a white background
dst += 255;
cv::cvtColor(dst, dst, CV_GRAY2BGR);
int x1,y1,x2,y2;
for(int i = 1; i < size.width; i += blockSize){
for(int j = 1; j < size.height; j += blockSize){
double tang = std::tan(angles.at<double>((i-1)/blockSize,(j-1)/blockSize));
if(tang >= -1 && tang <= 1){
x1 = i;
y1 = (-blockSize/2) * tang + j + blockSize/2;
x2 = i + blockSize;
y2 = (blockSize/2) * tang + j + blockSize/2;
}else{
x1 = i + blockSize/2 + blockSize/(2*tang);
y1 = j + blockSize/2;
x2 = i + blockSize/2 - blockSize/(2*tang);
y2 = j -blockSize/2;
}
cv::line(dst, cv::Point(x1,y1), cv::Point(x2,y2), cv::Scalar(0,0,255));
}
}
}
谢谢,我把它放在calculateAngles(角度)之后,它就起作用了。但是,如果我在这个函数内部转换并传递一个Mat&as参数,问题仍然存在。 –