我为提前:)这个解决方案很抱歉它做你需要什么,但:
create table TableA(
id int,
string varchar(255)
)
create table table2(
id varchar , text varchar(255)
)
insert into tableA values(1,'a,b,c,d')
insert into tableA values(2,'e,f')
insert into table2 values('a', 'value1')
insert into table2 values('b', 'value2')
insert into table2 values('c', 'value3')
insert into table2 values('d', 'value4')
insert into table2 values('e', 'value5')
insert into table2 values('f', 'value6')
select id, left(myConcat,len(myConcat)-1) from (
select c.id, replace(replace(CAST(CAST('<i'+stuff((select * from(
SELECT A.[id] ,
Split.a.value('.', 'VARCHAR(1000)') AS String
FROM (SELECT [id],
CAST ('<M>' + REPLACE([string], ',', '</M><M>') + '</M>' AS XML) AS String
FROM TableA) AS A CROSS APPLY String.nodes ('/M') AS Split(a)) a
inner join table2 b on a.String = b.id
where a.id = c.id
FOR XML PATH ('')
),1,2,'') AS XML).query('/text') AS VARCHAR(1000)),'<text>',''),'</text>',',') myConcat
from TableA c
group by c.id
) d
请显示你迄今尝试过的。 –
我甚至不完全确定从哪里开始。我正在考虑使用REPLACE函数,但是因为我不确定如何在每个值的字面意义上写REPLACE之外如何使用REPLACE函数。 –