图片 - 上传没有响应，到$ _FILES

Question

这里没有访问我的文件上传脚本，我收到以下错误

Notice: Undefined index: fupload in C:\Users\Tuskar\Desktop\Projekt\htdocs\Project IT-Space\Profile\edit_profile_parse.php on line 8 

但根据不应该有错误，因为我确定的指标。看起来我没有访问$ _FILES数组，因为之前我得到这个错误一直得到其他类似的错误或程序完全通过如果并直接去其他（文件没有选择）

我知道剧本是原始的，几乎不包括安全，但我只想在我添加其他功能，如最大文件大小或文件限制它第一工作... :(

这里是我使用的代码。

Upload Picture 
<form action="edit_profile_parse.php" method="get" enctype="multipart/form-data" > 
<input type="hidden" name="MAX_FILE_SIZE" value="999999999"> </input> 
<input type="file" name="fupload"> </input> 
<input type="submit" name="submit" value="Upload"> </input> 
</form> 

这里是处理表格的php

if (isset($_GET['submit'])) 
{ 
if (isset($_FILES['fupload'])) 
{ 
echo "name: ".$_FILES['fupload']['name']." <br> "; 
echo "size: ".$_FILES['fupload']['sizw']." <br> "; 
echo "type: ".$_FILES['fupload']['type']." <br> "; 

    if ($_FILES['fupload']['type'] == "image/gif") 
    { 
     $source = $_FILES['fupload']['tmp_name']; 
     $target = "images/" .$_FILES['fupload']['name']; 
     move_uploaded_file($source, $target) or die ("Error: " .mysql_error()); 
     $size = getImageSize($target); 

     $imgstr = "<img src=\" '".$target."' \">"; 
     echo $imgstr; 
    } 
    else 
    { 
    echo "Problem uploading the file ... "; 
    } 
} 
else 
{ 
echo "No file chosen !! "; 
} 
} 
else 
{ 
echo "Button not clicked "; 
} 

Answer 1

你应该使用form方法来POST而不是get。

<form action="edit_profile_parse.php" method="post" enctype="multipart/form-data" > 

Answer 2

确保您的FORM标记具有method =“POST”。 GET请求不支持多部分/表单数据上传。

Answer 3

上传图片

<form action="edit_profile_parse.php" method="POST" enctype="multipart/form-data" > 
<input type="hidden" name="MAX_FILE_SIZE" value="999999999"> </input> 
<input type="file" name="fupload"> </input> 
<input type="submit" name="submit" value="Upload"> </input> 
</form> 

PHP文件

<?php 
    if (isset($_POST['submit'])) 
    { 
    if (isset($_FILES['fupload'])) 
    { 
    echo "name: ".$_FILES['fupload']['name']." <br> "; 
    echo "size: ".$_FILES['fupload']['size']." <br> "; 
    echo "type: ".$_FILES['fupload']['type']." <br> "; 

     if ($_FILES['fupload']['type'] == "image/gif") 
     { 
      $source = $_FILES['fupload']['tmp_name']; 
      $target = "images/" .$_FILES['fupload']['name']; 
      move_uploaded_file($source, $target) or die ("Error: " .mysql_error()); 
      $size = getImageSize($target); 

      $imgstr = "<img src=\" '".$target."' \">"; 
      echo $imgstr; 
     } 
     else 
     { 
     echo "Problem uploading the file ... "; 
     } 
    } 
    else 
    { 
    echo "No file chosen !! "; 
    } 
    } 
    else 
    { 
    echo "Button not clicked "; 
    } 
    ?> 

Answer 4

我希望这个作品： 形式：

<form action="edit_profile_parse.php" method="post" enctype="multipart/form-data" > 
    <input type="hidden" name="MAX_FILE_SIZE" value="999999999"> </input> 
    <input type="file" name="fupload"> </input> 
    <input type="submit" name="submit" value="Upload"> </input> 
</form> 

php文件：

<?php 
if($_POST) { 
    $max_size = mysql_real_escape_string(strip_tags($_POST['MAX_FILE_SIZE'])); 
    $file = $_FILES['fupload']['name']; 

    if(isset($max_size) && !empty($max_size) && !empty($file)) { 
     $file_type = $_FILES['fupload']['type']; 
     $tmp = $_FILES['fupload']['tmp_name']; 
     $file_size = $_FILES['fupload']['size']; 

     $allowed_type = array('image/png', 'image/jpg', 'image/jpeg', 'image/gif'); 

     if(in_array($file_type, $allowed_type)) { 
      if($file_size < $max_size) { 
       $path = 'images/'.$file; 

       move_uploaded_file($tmp, $path); 
       //if you want to store the file in a db use the $path in the query 
      } else { 
       echo 'File size: '.$file_size.' is too big'; 
      } 
     } else { 
      echo 'File type: '.$file_type.' is not allowed'; 
     } 
    } else { 
     echo 'There are empty fields'; 
    } 
} 
?>