计算我有数据帧是这样的:的Python /大熊猫:基于单元格的值
A B C D E
0 2 3 4 8 7
1 4 7 5 9 4
2 3 4 5 7 2
3 8 9 1 3 7
我需要做这样的事情:
if 'value in column A' == 2:
'value for this row in new column' = 'value from column B' + 'value from column C'
elif 'value in column A' == 4:
'value for this row in new column' = 'value from column B' + 'value from column D'
elif 'value in column A' == 8:
'value for this row in new column' = 'value from column B' + 'value from column E'
else:
'value for this row in new column' = 0
我试图做这几种方法,例如:
1.
df['sum'][df['A'] == 2] = df['B'] + df['C']
df['sum'][df['A'] == 4] = df['B'] + df['D']
df['sum'][df['A'] == 8] = df['B'] + df['E']
2.
df.loc[df['A'] == 2, 'sum'] = df['B'] + df['C']
df.loc[df['A'] == 4, 'sum'] = df['B'] + df['D']
df.loc[df['A'] == 8, 'sum'] = df['B'] + df['E']
但我在结果中有空单元格。
您的解决方案不处理其他cas即您可能需要将呼叫传递给[fillna](https://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.fillna.html),例如'df.fillna(0,axis = 1)'在处理了前三种情况后。 – Quickbeam2k1