将列表合并到矩阵中

Question

我试图在Python中将5个列表合并成一个2d矩阵。名单被命名为A0 ... A4（所有相同长度的）

while (i <= len(a0)): 
    while (k < 5): 
     matrix[i][k] = #here I want to assign a0[i], a1[i],..., a5[i] 
     k+=1 
    i+=1 

有没有一种方法，使这项工作或做我必须去的东西，如：

while (i <= len(a0)): 
     matrix[i][0] = a0[i] 
     matrix[i][1] = a1[i] 
      .... 

Answer 1

如果A0通过a4已经是列表...你只需要把他们全部放入一个大列表。

让我知道这对你的作品：

a0 = [str(x) for x in range(10)] 
a1 = [str(x) for x in range(10, 20)] 
a2 = [str(x) for x in range(20, 30)] 
a3 = [str(x) for x in range(30, 40)] 
a4 = [str(x) for x in range(40, 50)] 

print("a0: {}".format(", ".join(a0))) 
print("a1: {}".format(", ".join(a1))) 
print("a2: {}".format(", ".join(a2))) 
print("a3: {}".format(", ".join(a3))) 
print("a4: {}".format(", ".join(a4))) 

matrix = [ 
    a0, 
    a1, 
    a2, 
    a3, 
    a4 
] 

# Below is another way: 
# matrix = [] 
# matrix.append(a0) 
# matrix.append(a1) 
# matrix.append(a2) 
# matrix.append(a3) 
# matrix.append(a4) 

print("matrix[3][4]: {}".format(matrix[3][4])) 

输出：

a0: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 
a1: 10, 11, 12, 13, 14, 15, 16, 17, 18, 19 
a2: 20, 21, 22, 23, 24, 25, 26, 27, 28, 29 
a3: 30, 31, 32, 33, 34, 35, 36, 37, 38, 39 
a4: 40, 41, 42, 43, 44, 45, 46, 47, 48, 49 
matrix[3][4]: 34