2016-04-23 42 views
0

我目前接收下列消息:非类类型的错误,和指针发出

错误从阿尔杜伊诺IDE接收:对构件“EEPROMWriteAny”在“ETYPE” 请求,其是非类类型“的EEPROMAnyType()'

我不认为我通过引用正确地在我的代码中传递变量,因为这似乎是导致上面写的错误的主要问题。 或者在一个类的类中有EEPROMWriteAny和EEPROM ReadAny是什么导致这个错误?我必须指向EEPROMAnyType类,然后指向U类吗? EEPROMReadAny甚至在嵌套类中吗?

我使用EEPROM库提供了头文件,cpp源文件,arduino示例代码以及如何定义下面类的关键字。 我也提供了一个图片,说明我的库在它的文件夹中的样子,以防出现问题。

头文件

#ifndef EEPROMAnyType_h 
#define EEPROMAnyType_h 

#include <Arduino.h> 
#include <EEPROM.h> 

class EEPROMAnyType 
{ 
    public: 
     template <class U> int EEPROMReadAny(unsigned int addr, U& x); //Reads any type of variable EEPROM 
     template <class U> int EEPROMWriteAny(unsigned int addr, U& x);//Writes any type of variable to EEPROM 
    private: 
     int i; 
     const byte *p[]; 
     byte *p[]; 
}; 

#endif 

CPP文件:

#include "Arduino.h" 
#include "EEPROM.h" 
#include "EEPROMAnyType.h" 

template <class U> int EEPROMAnyType::EEPROMReadAny(unsigned int addr, U x) 
{ 
    int i; 
    byte* p[sizeof(x)] = (byte*)(void*) x; //(void*) makes variable x "typeless" and then (byte*) casts the typeless variable as a byte type 
    for(i = 0; i < sizeof(x); i++){ // Why can I not declare i as an integer in the for loop? 
    p[i]= EEPROM.read(addr+i); 
    } 
    return i; 
} 
template <class U> int EEPROMAnyType::EEPROMWriteAny(unsigned int addr, U x) 
{ 
    int i = 0; 
    const byte* p[i] = (const byte*)(const void*) x; 
    for(i = 0; i < sizeof(x); i++){ 
    EEPROM.write(addr+i, p[i]); 
    } 
    return i; 
} 

的Arduino代码:

#include <Arduino.h> 
#include <EEPROM.h> 
#include <EEPROMAnyType.h> 


EEPROMAnyType eType(); // used to call EEPROMAnyType which can write/read any kind of data type to/from EERPOM 
int addr = 10; //memory location to be pass by value to EEPROMAnyType functions 
String *p;// To pass by reference to EEPROMAnyType functions 
String x; //will be assigned to EEPROM location 

void setup() { 
    x = "memory"; 
    p = &x; 
    Serial.begin(9600); 
    Serial.println("Hello World"); //shows start point of code 
    eType.EEPROMWriteAny(addr, *p); //Writes to EEPROM memory 10 
    x = eType.EEPROMReadAny(addr, *p); //assigns bytes from EEPROM memory location to x 
} 

void loop() { 
    Serial.print("x: "); 
    Serial.println(x); 
    Serial.print("no. of bytes stored in x: "); 
    Serial.println(EEPROMWriteAny(addr, p)); 
    delay(1000); 
} 

这里是我定义的关键字为类EPPROMAnyType:

EEPROMAnyType KEYWORD1 
EEPROMReadAny KEYWORD2 
EEPROMWriteAny KEYWORD2 

enter image description here

+1

'EEPROMAnyType eType();'应该是'EEPROMAnyType eType;'如果你想有一个实例。否则,你只是声明一个名为'eType'的函数。 –

回答

0

EEPROMAnyType eType(); - 编译器将该语句解释为函数声明,其名称为eType,并且它的返回类型为EEPROMAnyType。因此,eType不会是EEPROMAnyType的一个实例,从类的实例意义上来说eType的任何使用都会产生错误。希望这可以帮助。

+0

太棒了!谢谢!我在代码中发现了其他一些问题,但现在我正在通过它们。如果再次卡住,我一定会再次发帖。 –