SQL - 获取行，其中一列的比例大于另一列的比例

Question

我需要获取行的位置，其中一列的比例大于另一列的比例。

所以说我有2列：

• InventoryLevel int
• InventoryAlert int

我需要得到所有行InventoryLevel比InventoryAlert大于25％。

是否有可能在一个查询中执行所有操作？任何帮助将不胜感激！

Answer 1

SELECT InventoryLevel, 
     InventoryAlert 
FROM YourTable 
WHERE InventoryLevel > 1.25 * InventoryAlert 
/*Incorrect for stated question but meets clarification in comment 
    "InventoryLevel is any value greater than 25%, doesn't have to be exact. "*/ 

Answer 2

SELECT * 
FROM YourTable 
WHERE InventoryLevel = 1.25*InventoryAlert -- Or Maybe >= ?