所以我的计划是为了操纵某个坐标,以创造这一形象: 绘制随机界蟒蛇斜率
所以基本上我的计划画一堆随机圈,我必须处理的行公式来创建红色部分。到目前为止,我的图像如下:
我似乎无法弄清楚如何添加另一条线方程来创建另一个红色部分。任何帮助将不胜感激!
# using the SimpleGraphics library
from SimpleGraphics import *
# tell SimpleGraphics to only draw when I use the update() function
setAutoUpdate(False)
# use the random library to generate random numbers
import random
# size of the circles drawn
diameter = 15
resize(600, 400)
##
# returns a vaid color based on the input coordinates
#
# @param x is an x-coordinate
# @param y is a y-coordinate
# @return a colour based on the input x,y values for the given flag
##
def define_colour(x,y):
##
#add your code to this method and change the return value
slopeOne = (200 - 300)/(0-150)
b = 0 - (slopeOne * 200)
slopeTwo = (0-300)/(200 - 800)
b = 150 - (slopeTwo * 40)
lineEquationOne = (slopeOne * x) + b
lineEquationTwo = (slopeTwo * x) + b
if y > lineEquationOne:
return "red"
elif y > lineEquationTwo:
return "red"
else:
return 'white'
######################################################################
#
# Do NOT change anything below this line
#
######################################################################
# repeat until window is closed
while not closed():
for i in range(500):
# generate random x and y values
x = random.randint(0, getWidth())
y = random.randint(0, getHeight())
# set colour for current circle
setFill(define_colour(x,y))
# draw the current circle
ellipse(x, y, diameter, diameter)
update()
SimpleGraphics库从哪里来?我们如何获得副本? – martineau