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我在下面的php中得到以下错误,这是用来从mysql数据库中获取图表信息。欣赏的帮助mysqli_query(),mysqli_select_db()期望至少2个参数
警告:mysqli_query()预计至少2个参数,1 C中给出:\瓦帕\ WWW \第5行 警告试验\ getuser.php:mysqli_select_db()期望的是2个参数, 1在C中给出:\瓦帕\ WWW \第6行 呼叫未定义的函数mysqli_fetch测试\ getuser.php()在C:\瓦帕\ WWW \达达\ getuser.php上线18
PHP,
<?php
header("Content-type=text/json;charset=UTF-8");
$aVar = mysqli_connect('localhost', 'root', '123');
mysqli_query("set names utf-8");
mysqli_select_db("test");
$resultset = mysqli_query($aVar,"SELECT name, age FROM echartsuser");
$data = array();
class User{
public $username;
public $age;
}
while($row = mysqli_fetch_assoc($resultset);
$user = new User();
$user->username = $row['name'];
$user->age = $row['age'];
$data[] = $user;
}
mysqli_close();
echo json_encode($data);
?>
正如错误告诉你 –
尝试Google提问的标题 –
看到:http://stackoverflow.com /问题/ 23484158/mysqli的查询-预计-AT-至少-2-参数-1-给出式 –