2013-10-02 96 views
0

我做了一个PHP页面,应该从数据库中选择两个名称并显示它们。警告:mysqli_query()需要至少2个参数,给定1。什么?

它只是说:

Warning: mysqli_query() expects at least 2 parameters, 1 given in /home/tdoylex1/public_html/dorkhub/index.php on line 4 

Warning: mysqli_query() expects at least 2 parameters, 1 given in /home/tdoylex1/public_html/dorkhub/index.php on line 8 

我的代码是:

<?php mysqli_connect(localhost,tdoylex1_dork,dorkk,tdoylex1_dork); 
$name1 = mysqli_query("SELECT name1 FROM users 
ORDER BY RAND() 
LIMIT 1"); 

$name2 = mysqli_query("SELECT name FROM users 
ORDER BY RAND() 
LIMIT 1"); 

?> 

<title>DorkHub. The online name-rating website.</title> 
<link rel="stylesheet" type="text/css" href="style.css"> 
<body bgcolor='EAEAEA'> 
<center> 
<div id='TITLE'> 
    <h2>DorkHub. The online name-rating website.</h2> 
</div> 
    <p> 
    <br> 
    <h3><?php echo $name1; ?></h3><h4> against </h4><h3><?php echo $name1; ?></h3> 
    <br><br> 
    <h2 style='font-family:Arial, Helvetica, sans-serif;'>Who's sounds the dorkiest?</h2> 
    <br><br> 
    <div id='vote'> 
    <h3 id='done' style='margin-right: 10px'>VOTE FOR FIRST</h3><h3 id='done'>VOTE FOR LAST</h3> 
+3

您缺少一个参数。 http://php.net/manual/en/mysqli.query.php – Schleis

+1

做编程的第一课:如果错误信息显示你错过了某些东西,那么很可能你错过了那个东西。 –

+0

[mysqli \ _query可能至少需要2个参数](http://stackoverflow.com/questions/8073278/mysqli-query-expects-at-least-2-parameters) – JasonMArcher

回答

17

的问题是,你没有保存的mysqli连接。更改您连接到:

$aVar = mysqli_connect('localhost','tdoylex1_dork','dorkk','tdoylex1_dork'); 

然后包括在您的查询:

$query1 = mysqli_query($aVar, "SELECT name1 FROM users 
    ORDER BY RAND() 
    LIMIT 1"); 
$aName1 = mysqli_fetch_assoc($query1); 
$name1 = $aName1['name1']; 

也不要忘记附上您连接变量为字符串,因为我有以上。这就是导致错误的原因,但是你使用的函数是错误的,mysqli_query返回一个查询对象,但为了获得数据,你需要使用像mysqli_fetch_assoc http://php.net/manual/en/mysqli-result.fetch-assoc.php这样的数据来实际地将数据输出到一个变量中,如上所述。

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