该错误应该是正确的代码？ mysqli_query（）需要至少2个参数，其中1个参数在

Question

这段代码中有一个错误。 您能帮我调试吗？

<?php 
function pagination($query, $per_page = 10,$page = 1, $url = '?'){   
    $query = "SELECT COUNT(*) as `num` FROM {$query}"; 
    $row = mysqli_fetch_array(mysqli_query($query)); 
    $total = $row['num']; 
    $adjacents = "2"; 

    $page = ($page == 0 ? 1 : $page); 
    $start = ($page - 1) * $per_page;        

    $prev = $page - 1;       
    $next = $page + 1; 
    $lastpage = ceil($total/$per_page); 
    $lpm1 = $lastpage - 1; 

Answer 1

您不使用OOP的风格，所以你必须把你的数据库链接作为第一个参数。其次是查询本身。

$dblink = mysqli_connect("localhost","my_user","my_password","my_db"); 

... 

function pagination($query, $per_page = 10,$page = 1, $url = '?', $dblink) 
{ 
    $query = "SELECT COUNT(*) as num FROM {$query}"; 
    $row = mysqli_fetch_array(mysqli_query($dblink, $query)); 
    $total = $row['num']; $adjacents = "2"; 
}