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我正在使用画布加载图像。在图像上绘制一些线条。然后,我想点击一个“翻转”按钮来翻转图像和我刚画出的线条。代码是here on jsfiddle。翻转图像和HTML5画布中绘制的线条
我现在的问题是:
- 我绘制线条将不会翻转,但图像翻转后,我 点击“翻转”按钮。
- 在我点击“翻页”按钮后,线条将不会立即显示“ ”。当我开始再次绘制 时,线条会显示。
任何帮助将不胜感激。
感谢,
var context;
var canvas;
var imageObj = new Image();
var flipH = true;
var flipV = true;
var scaleH = 1,
scaleV = 1;
var posX = 0,
posY = 0;
var isDrawingFreeDraw;
canvas = document.getElementById('myCanvas');
context = canvas.getContext('2d');
context.strokeStyle = "#FFFF00";
//context.save();
canvas.addEventListener('mousedown', MouseDown, true);
canvas.addEventListener('mouseup', MouseUp, true);
canvas.addEventListener('mousemove', MouseMove, true);
imageObj.src = 'http://upload.wikimedia.org/wikipedia/commons/1/1a/Image_upload_test.jpg';
imageObj.onload = function() {
context.drawImage(imageObj, posX, posY, canvas.height * imageObj.width/imageObj.height, canvas.height);
};
console.log(context);
$(document).on('click', '#FlipH', function() {
console.log("Flip Me");
// context.restore();
context.save();
//canvas.width = 100;
scaleH = flipH ? -1 : 1;
context.scale(scaleH, scaleV);
posX = flipH ? (canvas.height * imageObj.width/imageObj.height) * -1 : 0;
context.drawImage(imageObj, posX, posY, canvas.height * imageObj.width/imageObj.height, canvas.height);
flipH = !flipH;
context.scale(1, 1);
//console.log(context);
context.restore();
});
function MouseUp(e) {
isDrawingFreeDraw = false;
context.save();
}
function MouseDown(e) {
context.save();
isDrawingFreeDraw = true;
console.log(e);
context.moveTo(e.pageX, e.pageY);
context.restore();
}
function MouseMove(e) {
if (isDrawingFreeDraw) {
context.save();
context.lineTo(e.pageX, e.pageY);
context.stroke();
context.restore();
}
}
巨大的。谢谢 – ttkrpink