如何在收到短信时使用PendingIntent启动应用程序？

Question

我需要启动一个应用程序时，只收到来自特定号码和某个端口的SMS。如果应用程序已经运行，我需要解析这个消息。我如何使用PendingIntent来做到这一点？

Answer 1

首先让接收这样的消息的broadcastreceiver类。 并在收到短信时触发你班级的意图。

class SMSReceiver extends BroadcastReceiver { 
    @Override 
    public void onReceive(Context context, Intent intent) { 
    Bundle bundle = intent.getExtras(); 
    SmsMessage[] msgs = null; 
    String str = ""; 
    if (bundle != null) { 
     Object[] pdus = (Object[]) bundle.get("pdus"); 
     msgs = new SmsMessage[pdus.length]; 
     for (int i = 0; i < msgs.length; i++) { 
     msgs[i] = SmsMessage.createFromPdu((byte[]) pdus[i]); 
     str += "SMS from " + msgs[i].getOriginatingAddress(); 
     str += " :"; 
     str += msgs[i].getMessageBody().toString(); 
     str += "\n"; 
     } 
     Toast.makeText(context, str, Toast.LENGTH_SHORT).show(); 
     Intent mainActivityIntent = new Intent(context, SMS.class); 
     mainActivityIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); 
     context.startActivity(mainActivityIntent); 
     Intent broadcastIntent = new Intent(); 
     broadcastIntent.setAction("SMS_RECEIVED_ACTION"); 
     broadcastIntent.putExtra("sms", str); 
     context.sendBroadcast(broadcastIntent); 
    } 
    } 
} 

存储在字符串中作为sms_sender

String msg_sender=msg[0].getOriginatingAddress(); 

和接收到消息后，得到的条件是

if(msg_sender=(String)"your_unique_number") 
    and fire the intent of your class if this condition is true.