我有两个数组(两者长度相同),我试图遍历两个数组中的每个元素,并测试这些元素(它们的是否相同索引)是否相等。我想得到相同的数字和不相等的数字。我已经能够使用while
循环做到这一点,但我想知道System.Linq
扩展是否有更快的方法?获取相同索引处相同元素的数量
这就是我现在所拥有的:
var list1 = new List<Color>
{
Color.Aqua,
Color.AliceBlue,
Color.Beige,
Color.Red,
Color.Green,
Color.White
};
var list2 = new List<Color>
{
Color.Red,
Color.BurlyWood,
Color.Beige,
Color.Azure,
Color.Green,
Color.Magenta
};
var enumFirst = list1.GetEnumerator();
var enumSecond = list2.GetEnumerator();
var equal = 0;
var notEqual = 0;
while (enumFirst.MoveNext() && enumSecond.MoveNext())
{
var colorFirst = enumFirst.Current;
var colorSecond = enumSecond.Current;
if (colorFirst == colorSecond)
equal++;
else
notEqual++;
}
Console.WriteLine("Elements that are equal: " + equal);
Console.WriteLine("Elements that are not equal: " + notEqual);
输出是:
Elements that are equal: 2
Elements that are not equal: 4