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我想在TensorFlow中编写this纸张的实现,并且遇到了一些问题。在我的合并图层中,我必须将所有内容连接在一起。这是我使用的代码:如何连接“锯齿”张量
pooled_outputs = []
for i, filter_size in enumerate(filter_sizes):
with tf.name_scope("conv-maxpool-%s" % filter_size):
# Conv layer
filter_shape = [filter_size, embedding_size, 1, num_filters]
# W is the filter matrix
W = tf.Variable(tf.truncated_normal(filter_shape, stddev=0.1), name="W")
b = tf.Variable(tf.constant(0.1, shape=[num_filters]), name="b")
conv = tf.nn.conv2d(
self.embedded_chars_expanded,
W,
strides=[1, 1, 1, 1],
padding="VALID",
name="conv"
)
# Apply nonlinearity
h = tf.nn.relu(tf.nn.bias_add(conv, b), name="relu")
# Max-pooling layer over the outputs
pooled = tf.nn.max_pool(
h,
ksize=[1, sequence_lengths[i] - filter_size + 1, 1, 1],
strides=[1, 1, 1, 1],
padding="VALID",
name="pool"
)
pooled_outputs.append(pooled)
# Combine all of the pooled features
num_filters_total = num_filters * len(filter_sizes)
print(pooled_outputs)
pooled_outputs = [tf.reshape(out, ["?", 94, 1, self.max_length]) for out in pooled_outputs] # The problem line
self.h_pool = tf.concat(3, pooled_outputs)
当我运行这段代码,它打印出此为pooled_outputs
:
[<tf.Tensor 'conv-maxpool-3/pool:0' shape=(?, 94, 1, 128) dtype=float32>, <tf.Tensor 'conv-maxpool-4/pool:0' shape=(?, 51, 1, 128) dtype=float32>, <tf.Tensor 'conv-maxpool-5/pool:0' shape=(?, 237, 1, 128) dtype=float32>]
我最初试图未经pooled_outputs = [tf.reshape(out, ["?", 94, 1, self.max_length]) for out in pooled_outputs]
行的代码在那里,我得到这个错误:
ValueError: Dimension 1 in both shapes must be equal, but are 51 and 237
当我在重塑行补充说,我得到这个错误:
TypeError: Expected binary or unicode string, got 94
我知道的第二个错误是因为我通过了一个“?”对于新的尺寸,我认为第一个错误是因为张量不是相同的尺寸。 我该如何正确放置这些张量器,以便我可以连接它们而不会出现问题?