2017-06-16 33 views
0

我从Firebase检索数据,然后将收到的类型为FIRDataSnapshot的数组转换为类型为[String:Any]的字典数组。 如何将这个字典数组输出到我的Xcode项目中的.txt文件的有序列表中?如何将字典数组写入Xcode项目中的.txt文件

输出在txt文件印刷应该在这个格式:

预订1:
EmailAddress的:[email protected]
电话号码:94949392


预订4:
EmailAddress的:[email protected]
电话号码:202583963

我的问题的底部,你会发现原始数据,它的外观在finalDictionary

我觉得逻辑应是这样的: 1.遍历的finalDictionary 2.元素采取数组的每个元素,分配一个计数到它+断裂线

let finalDictionary = [String:Any]() 

func startObservingDB() { 

    dbRef.child(FullData.uid!).observe(.value, with: { (snapshot: FIRDataSnapshot) in 

     // an instance of FireBaseData holding all bookings under currentUid 
     var newBookingInfo = [FireBaseData]() 

//iterate over all children under /FullData.uid! path 
    for customer in snapshot.children { 

     //the customer node starting with cus... 
     let customerObject = customer as! FIRDataSnapshot 

     //customer key 
      self.customerKey = customerObject.key 
      print("this is the Stripe customer that can be charged \(customerObject.key)") 

    //now iterate over each booking which is located under customerObject in Firebase 
    for booking in customerObject.children { 


     // after each iteration through snapshot.children, create an instance of FireBaseData with 'booking' for the current iteration & assign it to bookingItem 
      var bookingItem = FireBaseData(snapshot: booking as! FIRDataSnapshot) 

     //assign key of the parent to each booking 
       bookingItem.Key = self.customerKey 

      // append the bookingItem after each iteration to newBookingInfo array 
      newBookingInfo.append(bookingItem) 

     } // end of for booking in myCustomer 
    } // end of for customer in snapshot.children 

     //assign newBookingInfo to global variable bookingInfo so it can be used globally within the class 
     self.bookingInfo = newBookingInfo 

    // sort the array in place so that the most recent date will appear first 
self.bookingInfo.sort(by: {(DateAndTimeObject_1,DateAndTimeObject_2) -> Bool in 

    DateAndTimeObject_1.TimeStampDateAndTime > DateAndTimeObject_2.TimeStampDateAndTime 
    }) 


    // convert bookingInfo of type FIrebaseData to Array of Dictionaries 
    let arrayOfDictionary = self.bookingInfo.flatMap { $0.toAnyObject() as? [String:Any] } 

    finalDictionary = arrayOfDictionary 
    print("arrayOfDictionary is \(arrayOfDictionary)") 

//I can write a string to a file in Xcode project using the code snippet 
//below, but this does not solve my problem, namely to output all elements 
//of the array as specified above with a break space after each element 
//so that they can be in a human readable format. 

let fileName = "myBookings" 
    let dir = try? FileManager.default.url(for: .documentDirectory, in: .userDomainMask, appropriateFor: nil, create: true) 

    // If the directory was found, we write a file to it 
    if let fileURL = dir?.appendingPathComponent(fileName).appendingPathExtension("txt") { 

    // Write to the file 
    let outString = "Write this text to the file" 
    do { 
     try outString.write(to: fileURL, atomically: true, encoding: .utf8) 
    } catch { 
     print("Failed writing to URL: \(fileURL), Error: " + error.localizedDescription) 
    } 
} 




      self.tableView.reloadData() 
     }, withCancel: { (Error:Any) in 
     print("Error firebase \(Error)") 
    }) 
    } // end of startObservingDB() 



func exportBookings(){ 

let path = URL(string: "file:///Users/bogdanbarbulescu/Desktop/Test.txt") 

     //writing 
     do { 
      try (finalDictionary).description.write(to: path!, atomically: false, encoding: .utf8) 
     } 
     catch let error { print("The error is \(error.localizedDescription)") 
    } 
} 

打印的输出( “arrayOfDictionary是(arrayOfDictionary)”)是:

arrayof字典是[[ “EmailAddress的”:[email protected], “******中国”: 94949392, “PaymentID”:ch_1AVK6KLCZ34Ur7XGsbROjWhe “BookingAmount”: 37,“BookingCompleted”:0,“NoteInstructions”:请把狗取出 please,“insideCabinets”:true,“BookingNumber”:883924391, “BookingStatusAdmin”:0,“insideFridge”:true, “FrequencyName”:每个 2周,“EntryInstructions”:地毯下的键,“FullName”:James, “SuppliesAmount”:0,“FirebaseUserID”:7b1eRsa9QWhdtA5EwyD2FiPZHSh2, “TimeStampDate AndTime“:1497790800,”PostCode“:W3 7RZ, ”SelectedBathRow“:2,”FrequecyAmount“:22,”laundryWash“:false, ”StreetAddress“:11 High St,”CostToRescheduleClient“:0, ”BookingStatusClient“ :1,“TimeStampBookingSavedInDB”:1497618179, “FlatNumber”:Conely,“SelectedBedRow”:1,“interiorWindows”:0, “CostToCancelClient”:0,“DoormanOption”:隐藏键,“DateAndTime”: Sun, 2017年6月18日14:00,“insideOven”:true,“SuppliesName”:我有 清洁用品],

[“EmailAddress”:johnmm @ gmail。COM, “******中国”:07476953923, “PaymentID”:ch_1ATTRHLCZ34Ur7XGL2CGN1I3, “BookingAmount”:63, “BookingCompleted”:0, “NoteInstructions”:不, “insideCabinets”:真实, “BookingNumber”:173009560, “BookingStatusAdmin” :1,“insideFridge”: true,“FrequencyName”:每2周“EntryInstructions”:simbasdada, “CostToRescheduleAdmin”:0,“FullName”:John Luch,“SuppliesAmount”: 5,“FirebaseUserID”:7b1eRsa9QWhdtA5EwyD2FiPZHSh2 , “TimeStampDateAndTime”:1497632400, “邮编”:IG11 6PP, “SelectedBathRow”:2 “FrequecyAmount”:33, “laundryWash”:真, “的StreetAddress”:高圣, “CostToRescheduleClient”:0, “ BookingStatusClient“:1,”TimeStampBookingSavedInDB“:1497177419, “FlatNumber”:Flat 11,“SelectedBedRow”:2,“interiorWindows”:0, “DoormanOption”:隐藏键,“DateAndTime”:2017年6月16日星期五18:00, “insideOven”:false, SuppliesName“:把清洁用品]

+2

在iOS中没有桌面。所以我想答案是,你不能。 – dasdom

+0

@dasdom嗯,我可以制作一个桌面路径,然后使用'write(toFile:atomically:)'来编写一个字符串从Xcode到桌面。它的工作原理,但我不知道如何排列数组中的元素。基本上,上面的函数接受一个字符串并将其写入路径。如何获取字典数组,将其转换为字符串,然后将其写入桌面的有序列表中? – bibscy

+0

'从Xcode到桌面'Xcode只是代码编辑器,它不是你的应用程序。如果您可以从*您的应用*写入您的Mac桌面,那么这意味着您的应用不是iOS应用,而是一款macOS应用。 //请解释并提供更多细节。 – Moritz

回答

1

如果你想要做的是你在字典的阵列输出‘有序/可读’的格式,您可以使用此:

if let orderedKeys = finalDictionary.first?.keys { 

    var outputString = "" 
    var i = 1 

    for d in finalDictionary { 
     outputString += "Booking \(i):\n" 
     for k in orderedKeys { 
      outputString += k + ": " + (d[k] ?? "(no value)") + "\n" 
     } 
     outputString += "\n" 
     i += 1 
    } 

    print(outputString) 
    // or, write outputString to a text file 

} 

注:此只是快速代码...不一定是最佳的或100%无错,并假定所有记录具有相同的密钥。更多的是“这里有一个方向去”还挺啄:)

编辑:大概:如果字典可以具有可变的钥匙套的,你可以这样做:

var outputString = "" 
var i = 1 
for d in finalDictionary { 
    outputString += "Booking \(i):\n" 
    for k in d.keys { 
     outputString += k + ": " + (d[k] ?? "(no value)") + "\n" 
    } 
    outputString += "\n" 
    i += 1 
} 

print(outputString) 

编辑2这样做有点“Swiftier”的方式:

outputString = "" 
i = 1 

finalDictionary.forEach { 
    outputString += "Booking \(i):\n" 
    $0.forEach { outputString += "\($0): \($1)\n" } 
    outputString += "\n" 
    i += 1 
} 

print(outputString) 

因为字典是无序的,你可能会结束

Booking 1: 
EmailAddress: [email protected] 
PhoneNumber: 94949392 
FullName: John 
. 
Booking 2: 
SomeOtherKey: Some Value 
FullName: Dave 
EmailAddress: [email protected] 
. 
Booking 3: 
FullName: Chris 
PhoneNumber: 202583963 
SomeOtherKey: Some Other Value 
EmailAddress: [email protected] 

等等。

+0

感谢您的帮助。但是,字典并不总是具有与用户可以决定写入新数据相同的密钥。 – bibscy

+0

请参阅我对“变量集键”的编辑 – DonMag

+0

finalDictionary是[String:Any]类型,在此行上'outputString + = k +“:”+(d [k] ??“(no value)”)+ “\ n”'我得到错误二进制运算符+不能应用于String类型的操作数和任何 – bibscy