初始化结构中的函数指针

Question

typedef struct foo{ 
    void (*del)(void *toDel); 
    char* (*p)(void *tp) 
} Foo; 

Foo init(char* (*print)(void*),void (*delFunc)(void*)); 

试图找出如何分配或初始化提供给struct函数指针的参数。

Answer 1

Foo init(char* (*print)(void *toBePrinted),void (*delFunc)(void *toBeDeleted)) 
{ 
    return Foo{ .del = delFunc, .p = print}; 
} 

这个是什么？龙形态：

Foo init(char* (*print)(void *toBePrinted),void (*delFunc)(void *toBeDeleted)) 
{ 
    Foo tmp = { 
     .del = delFunc, 
     .p = print 
    }; 
    return tmp; 
} 

Answer 2

How to initialize a struct in accordance with C programming language standards

你可以做到这一点的常用方法：

Return (Foo){.del=delFunc, .p=print}; 

Answer 3

的直线前进（最向后兼容的方法）来定义foo为Foo并初始化它：

Foo foo = { /* Mind the order of the following initialisers! */ 
    delFunc, 
    print 
};