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我面临的发展在Ruby中,参照有效的二进制搜索算法的一些问题this site
二进制搜索返回错误的值
正确答案:返回一个值-1432
接收的答案:无
代码如下:
def bsearch(a, k)
lower = 0
upper = a.length-1
while a[upper].to_f> k.to_f and a[lower].to_f< k.to_f
low_diff = k.to_f -a[lower].to_f
range_diff = a[upper].to_f-a[lower].to_f
count_diff = upper-lower
range = ((low_diff/range_diff) * (count_diff)) + lower
if k.to_f > a[range].to_f
lower = range+1
elsif k.to_f < a[range].to_f
upper =range-1
else
lower = range
end
end
if k =a[lower]
return lower
else
return nil
end
end
请帮我摆脱逻辑。
你知道['阵列#bsearch'(http://www.ruby-doc.org/core-2.0.0/Array.html#method-i-bsearch)你不是吗? – Stefan