如何打印第一个数组中的单词，第二个数组中的第二个和第三个数组中的第三个单词的组合？

Question

我想这段代码的输出有三个数组列表中的条目由逗号分隔为分隔符下面("slow,steady"),("blue, white,green")("whale, shark ");。它具有以下输出

slow blue whale 
slow white whale 
slow white shark 
steady blue whale 
steady white shark 
and so forth. 

我能够给每一个字分开，并把他们在三个单独的名单。 list1包含慢速稳定list2包含蓝色白色绿色和list3包含鲸鲨。但我无法连接它们。欢迎任何投入。

import java.util.StringTokenizer; 
import java.util.ArrayList; 
import java.util.List; 
import java.util.*; 

public class HelloWorld {  

    String input; //input String 
    StringBuffer output; //Holds the output 
    String delimiter = ","; //Delimiter (default comma (,)) 
    String arrayOfWords[]; 
    List<String> list1 = new ArrayList<String>(); 
    List<String> list2 = new ArrayList<String>(); 
    List<String> list3 = new ArrayList<String>(); 

    int listCount; 

    /* 
    * Generates combinations by applying the 
    * concept of recursion 
    */ 


    public void generateCombinations(String input, String delimiter,int listCount) 
    {  
      output = new StringBuffer();    
      this.input = input;  
      this.delimiter = delimiter; 
      this.listCount = listCount; 

       String[] stockArr = new String[list1.size()]; 
       String[] stockArr1 = new String[list2.size()]; 
       String[] stockArr2 = new String[list2.size()]; 

      if(listCount == 1) { 
       String items1[] = input.split(","); 
       for(int i=0;i< items1.length; i++){ 

       list1.add(items1[i]); 
       } 

      } 

      else if(listCount == 2) { 
       String items2[] = input.split(","); 
       for(int i=0;i< items2.length; i++){ 

       //System.out.println(items2[i]); 
       list2.add(items2[i]); 
       } 

      } 

      else { 
       String items3[] = input.split(","); 
       for(int i=0;i< items3.length; i++){ 

       // System.out.println(items3[i]); 
       list3.add(items3[i]); 
       } 

      } 


     stockArr = list1.toArray(stockArr); 
     stockArr1 = list2.toArray(stockArr1); 
     stockArr2 = list3.toArray(stockArr2); 


     for(String s1 : stockArr){ 

      System.out.print(s1);   
     }   


     for(String s2 : stockArr1){ 

      System.out.print(s2);  
    }   



     for(String s3 : stockArr2){ 

      System.out.print(s3);  
     }   


     for(int i=0;i<list1.size();i++){ 
     String s1 = list1.get(i).toString(); 
       for(int j=0;j<list2.size();j++){ 
        String s2 = list2.get(j).toString(); 
        System.out.println(s1+s2); 
       } 


    } 


} 

    public static void main(String[] args) {  
     ArrayList <String> strings = new ArrayList <String>(); 
     int i=1; 

     for(String string : strings){ 
     new HelloWorld().generateCombinations(string , ",",i); 
      ++i; 
     } 

    }  
} 

Answer 1

终于有了它的工作好:) 奖励：现在，这不要紧，你需要多少字来连接。

import java.util.*; 
import java.util.stream.*; 

public class Test { 

    public static void generateCombinations(ArrayList <String> strings, String delimiter){ 

     int stringsSize = strings.size(); 
     int i=0; 
     String text = ""; 
     parseList(text, stringsSize ,i, strings, delimiter); 

    } 

    public static void parseList(String text, int stringsSize, int i, ArrayList <String> strings, String delimiter) { 
     String stringStream = strings.get(i); 
     String[] list = stringStream.split(delimiter); 
     if (i==stringsSize-1) { 
      for (String string : list){ 
       System.out.println(text + " " + string.replaceAll("\\s+","")); 
      } 
     } else { 
      for (String string : list){ 
       String text2 = text + " " + string.replaceAll("\\s+",""); 
       int j = i+1; 
       parseList(text2, stringsSize, j, strings, delimiter); 
      } 
     } 
    } 

    public static void main(String[] args) {  
     ArrayList <String> strings = new ArrayList <String>(); 
     strings.add("slow,steady"); 
     strings.add("blue, white, green"); 
     strings.add("whale, shark "); 

     generateCombinations(strings , ","); 

    } 
} 

结果：

slow blue whale 
slow blue shark 
slow white whale 
slow white shark 
slow green whale 
slow green shark 
steady blue whale 
steady blue shark 
steady white whale 
steady white shark 
steady green whale 
steady green shark 

Answer 2

这可以使用嵌套for循环来完成。在你的情况下3层。

stockArr = list1.toArray(stockArr); 
    stockArr1 = list2.toArray(stockArr1); 
    stockArr2 = list3.toArray(stockArr2); 

    for (String a : stockArr) { 
     for (String b : stockArr1) { 
      for (String c : stockArr2) { 
       System.out.println(a + " " + b + " " + c); 
      } 
     } 
    } 

而且，它总是更好的性能，如果您使用StringBuilder到Concat的多个String。即

for (String a : stockArr) { 
     for (String b : stockArr1) { 
      for (String c : stockArr2) { 
       StringBuilder sb = new StringBuilder(); 
       sb.append(a) 
        .append(" ") 
        .append(b) 
        .append(" ") 
        .append(c); 
       System.out.println(sb.toString()); 
      } 
     } 
    } 

Answer 3

试试这个

public static void main(String[] args) { 

    List<String[]> afterSplit = new ArrayList<String[]>(); 
    afterSplit.add("slow, steady".split(",")); 
    afterSplit.add("blue, white, green".split(",")); 
    afterSplit.add("whale, shark ".split(",")); 
    for (int i = 0; i < afterSplit.get(0).length; i++) { 
     for (int j = 0; j < afterSplit.get(1).length; j++) { 
      for (int k = 0; k < afterSplit.get(2).length; k++) { 
       System.out.println(afterSplit.get(0)[i].trim() + " " 
         + afterSplit.get(1)[j].trim() + " " 
         + afterSplit.get(2)[k]); 

      } 
     } 

    } 

}