范围内的数字（）代码没有返回预期的结果

Question

我正在学习Python，现在正在使用简单的代码编写和if-elif-else语句。 我有这样的代码块，总是返回else语句，即使我把数字1和30

elif door == "3": 
     print "This is a winning treasure room, congratulations!" 
     print "Pick a number between 1 and 30" 

     number = raw_input ("> ") 

     if number in range (1,10): 
      print "that's a number between 1 and 10" 

     elif number in range (11, 20): 
      print "that's a number between 11 and 20" 

     elif number in range (21, 30): 
      print "that's a number between 21 and 30" 

     else: 
      print "that's not a number we asked for" 

之间我也然后设法：

elif door == "3": 
     print "This is a winning treasure room, congratulations!" 
     print "Pick a number between 1 and 30" 

     number = raw_input ("> ") 

     if number == number in range (1,10): 
      print "that's a number between 1 and 10" 

     elif number == number in range (11, 20): 
      print "that's a number between 11 and 20" 

     elif number == number in range (21, 30): 
      print "that's a number between 21 and 30" 

     else: 
      print "that's not a number we asked for" 

我也尝试：

if number == x in range (1, 10): 

但是，当然x没有定义，它会出现一个错误。

任何指导赞赏。

Answer 1

raw_input()将输入转换为字符串。您需要将其转换为整数。

number = int(raw_input ("> ")) 

的raw_input（）：

然后该功能可以读取从输入的线，将其转换成字符串 （剥离的后换行），并返回。

从doc