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我有这样一个数据帧的时间:绘制仅使用GGPLOT2
head(yy)
Team Date STime ETime
1 A 2012-03-06 07:03 10:13
2 A 2012-03-06 07:03 10:13
3 A 2012-03-06 07:03 10:13
4 A 2012-03-06 07:03 10:13
5 A 2012-03-06 07:03 10:13
6 A 2012-03-06 07:03 10:13
dput(YY)
dput(yy)
structure(list(Team = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "A", class = "factor"),
Date = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "2012-03-06", class = "factor"),
STime = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "07:03", class = "factor"),
ETime = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "10:13", class = "factor")), .Names = c("Team",
"Date", "STime", "ETime"), class = "data.frame", row.names = c(NA,
-50L))
我喜欢看的y轴从00:00 23:59在增加2小时,并能够在STime值上绘制红线。
我的财产以后这样的,但它看起来不正确:
ggplot(yy, aes(Date, ETime, group="Team")) + geom_jitter(size=0.05) + facet_wrap(~ Team) + geom_hline(yintercept=yy$Stime, colour="red", size=2)
你会如何在GGPLOT2做到这一点?有人能给我指示/启动我在正确的方向吗?
问候,
你可以发布结果'dput(df)'(或'dput(head(df))'如果它太大了,我们可以重现你的数据吗? –
@DavidRobinson,我只是放置了输出输出。 – user1471980
您的数据没有变化。如果你只是试图制作一个插图,你应该看一看[inkscape](http://inkscape.org/),它是一个很棒的免费软件 - 比如R. –