我正在一个自动化点胶项目,我打算控制十个不同的12V 600mA直流泵与Arduino。一种计算机在以下形式的USB连接到Arduino发送消息:控制电机与Arduino串行连接使用电脑
lh = pumps off
0h = pump 0 on
1h = pump 1 on
etc.
阿尔杜伊诺通过激活连接到12V 2A直流电源TIP120 npn型电阻器提供了电源泵。在任何给定时间只有一台泵将运行。
当我通过为LED供电进行测试时,串行连接完美无缺。然而,当我尝试使用泵时,Arduino开始对命令做出迟钝的反应,最终我失去了与Arduino的串行连接。我只能想象,会有某种权力问题导致Arduino失去联系。任何想法,我错了?
Arduino的代码:
#define PUMP5 5 //pin for turning transistor on/off
const byte numChars = 32;
char msg[numChars];
void setup() {
Serial.begin(9600,SERIAL_8N1);
Serial.println(msg[0]);
pinMode(PUMP5, OUTPUT);
}
void loop() {
read_msg();
command_pumps();
}
void read_msg() {
char rc;
if (Serial.available() > 0) {
rc = Serial.read();
msg[0] = rc;
}
if(Serial.available() > 0) {
rc = Serial.read();
msg[1] = rc;
}
Serial.print("msg[0]: ");
Serial.println(msg[0]);
Serial.print("msg[1]: ");
Serial.println(msg[1]);
}
//PUMP5 is used for each of the scenarios since I am only testing with one pump
void command_pumps() {
if (msg[0] == 'l'||msg[1]=='l') {
digitalWrite(PUMP5, LOW);
} else if (msg[1] == 'h') {
if(msg[0]=='0') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='1') digitalWrite(PUMP5, LOW);
else if (msg[0]=='2') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='3') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='4') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='5') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='6') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='7') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='8') digitalWrite(PUMP5, HIGH);
else if (msg[0]=='9') digitalWrite(PUMP5, HIGH);
}
return;
}
你在电源上做了什么?它有足够的容量吗? – barny
可能是二极管放置。请参阅https://electronics.stackexchange.com/questions/31014/where-should-i-put-the-kickback-diode-in-a-transistor-switch –
您能向我们展示该图吗?听起来就像你在这里丢失了适当的反激式二极管。 – user3411864