在Django中流式传输CSV文件

Question

我正尝试将csv文件作为附件下载进行流式处理。 CSV文件大小已达到4MB或更多，我需要一种方式让用户主动下载文件，而无需等待所有数据被创建并首先提交到内存。

我第一次使用我自己的文件包装基于Django的FileWrapper类。那失败了。然后我在这里看到了一种使用发电机来流的响应： How to stream an HttpResponse with Django

当我在发电机内产生一个错误，我可以看到，我创建与get_row_data()功能正确的数据，但是当我尝试返回它回复空的响应。我也禁用了Django GZipMiddleware。有谁知道我做错了什么？

编辑：我遇到的问题是与ConditionalGetMiddleware。我不得不更换它，代码在下面的答案。

这里是视图：

from django.views.decorators.http import condition 

@condition(etag_func=None) 
def csv_view(request, app_label, model_name): 
    """ Based on the filters in the query, return a csv file for the given model """ 

    #Get the model 
    model = models.get_model(app_label, model_name) 

    #if there are filters in the query 
    if request.method == 'GET': 
     #if the query is not empty 
     if request.META['QUERY_STRING'] != None: 
      keyword_arg_dict = {} 
      for key, value in request.GET.items(): 
       #get the query filters 
       keyword_arg_dict[str(key)] = str(value) 
      #generate a list of row objects, based on the filters 
      objects_list = model.objects.filter(**keyword_arg_dict) 
     else: 
      #get all the model's objects 
      objects_list = model.objects.all() 
    else: 
     #get all the model's objects 
     objects_list = model.objects.all() 
    #create the reponse object with a csv mimetype 
    response = HttpResponse(
     stream_response_generator(model, objects_list), 
     mimetype='text/plain', 
     ) 
    response['Content-Disposition'] = "attachment; filename=foo.csv" 
    return response 

这里是我使用流式传输的响应发电机：

def stream_response_generator(model, objects_list): 
    """Streaming function to return data iteratively """ 
    for row_item in objects_list: 
     yield get_row_data(model, row_item) 
     time.sleep(1) 

，这里是我如何创建CSV行数据：

def get_row_data(model, row): 
    """Get a row of csv data from an object""" 
    #Create a temporary csv handle 
    csv_handle = cStringIO.StringIO() 
    #create the csv output object 
    csv_output = csv.writer(csv_handle) 
    value_list = [] 
    for field in model._meta.fields: 
     #if the field is a related field (ForeignKey, ManyToMany, OneToOne) 
     if isinstance(field, RelatedField): 
      #get the related model from the field object 
      related_model = field.rel.to 
      for key in row.__dict__.keys(): 
       #find the field in the row that matches the related field 
       if key.startswith(field.name): 
        #Get the unicode version of the row in the related model, based on the id 
        try: 
         entry = related_model.objects.get(
          id__exact=int(row.__dict__[key]), 
          ) 
        except: 
         pass 
        else: 
         value = entry.__unicode__().encode("utf-8") 
         break 
     #if it isn't a related field 
     else: 
      #get the value of the field 
      if isinstance(row.__dict__[field.name], basestring): 
       value = row.__dict__[field.name].encode("utf-8") 
      else: 
       value = row.__dict__[field.name] 
     value_list.append(value) 
    #add the row of csv values to the csv file 
    csv_output.writerow(value_list) 
    #Return the string value of the csv output 
    return csv_handle.getvalue() 

Answer 1

下面是一些简单的代码，可以流式传输CSV;你或许可以去从这个到任何你需要做的：

import cStringIO as StringIO 
import csv 

def csv(request): 
    def data(): 
     for i in xrange(10): 
      csvfile = StringIO.StringIO() 
      csvwriter = csv.writer(csvfile) 
      csvwriter.writerow([i,"a","b","c"]) 
      yield csvfile.getvalue() 

    response = HttpResponse(data(), mimetype="text/csv") 
    response["Content-Disposition"] = "attachment; filename=test.csv" 
    return response 

这只是每一行写入内存中的文件，读取该行并得到它。

这个版本是用于产生批量数据更高效的，但要确保在使用它之前，了解上述：

import cStringIO as StringIO 
import csv 

def csv(request): 
    csvfile = StringIO.StringIO() 
    csvwriter = csv.writer(csvfile) 

    def read_and_flush(): 
     csvfile.seek(0) 
     data = csvfile.read() 
     csvfile.seek(0) 
     csvfile.truncate() 
     return data 

    def data(): 
     for i in xrange(10): 
      csvwriter.writerow([i,"a","b","c"]) 
     data = read_and_flush() 
     yield data 

    response = HttpResponse(data(), mimetype="text/csv") 
    response["Content-Disposition"] = "attachment; filename=test.csv" 
    return response 

Answer 2

我是有问题是与ConditionalGetMiddleware。我看到Django的活塞拿出一个替代中间件为ConditionalGetMiddleware允许流：从一个聪明的回答

from django.middleware.http import ConditionalGetMiddleware 

def compat_middleware_factory(klass): 
    """ 
    Class wrapper that only executes `process_response` 
    if `streaming` is not set on the `HttpResponse` object. 
    Django has a bad habbit of looking at the content, 
    which will prematurely exhaust the data source if we're 
    using generators or buffers. 
    """ 
    class compatwrapper(klass): 
     def process_response(self, req, resp): 
      if not hasattr(resp, 'streaming'): 
       return klass.process_response(self, req, resp) 
      return resp 
    return compatwrapper 

ConditionalMiddlewareCompatProxy = compat_middleware_factory(ConditionalGetMiddleware) 

，那么你将与你的ConditionalMiddlewareCompatProxy中间件更换ConditionalGetMiddleware，并在您的视图（借来的代码这个问题）：

def csv_view(request): 
    def data(): 
     for i in xrange(10): 
      csvfile = StringIO.StringIO() 
      csvwriter = csv.writer(csvfile) 
      csvwriter.writerow([i,"a","b","c"]) 
      yield csvfile.getvalue() 

    #create the reponse object with a csv mimetype 
    response = HttpResponse(
     data(), 
     mimetype='text/csv', 
     ) 
    #Set the response as an attachment with a filename 
    response['Content-Disposition'] = "attachment; filename=test.csv" 
    response.streaming = True 
    return response 

Answer 3

中间件的问题已经得到解决的Django的1.5和StreamingHttpResponse已经出台。下面应该做的：

import cStringIO as StringIO 
import csv 

def csv_view(request): 
    ... 
    # Assume `rows` is an iterator or lists 
    def stream(): 
     buffer_ = StringIO.StringIO() 
     writer = csv.writer(buffer_) 
     for row in rows: 
      writer.writerow(row) 
      buffer_.seek(0) 
      data = buffer_.read() 
      buffer_.seek(0) 
      buffer_.truncate() 
      yield data 
    response = StreamingHttpResponse(
     stream(), content_type='text/csv' 
    ) 
    disposition = "attachment; filename=file.csv" 
    response['Content-Disposition'] = disposition 
    return response 

有上how to output csv from Django一些文档，但它并没有充分利用StreamingHttpResponse所以我继续opened a ticket in order to track it。