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我有一个脚本的入站缓冲区数据,我需要key =>'value'以便我可以对它运行一个数学方程(是的,我知道我需要转换为int) 。由于我确定数据是字符串,我试图对它进行模式匹配。 我看到入站数据,但我从未得到正面匹配。C++字符串模式匹配缓冲区数据
代码:从print_f输出
int getmyData()
{
char key[] = "total";
char buff[BUFSIZ];
FILE *fp = popen("php getMyorders.php 155", "r");
while (fgets(buff, BUFSIZ, fp)){
printf("%s", buff);
//if (strstr(key, buff) == buff) {
if (!memcmp(key, buff, sizeof(key) - 1)) {
std::cout << "Match "<< std::endl;
}
}
}
数据():
array(2) {
["success"]=>
string(1) "1"
["return"]=>
array(3) {
[0]=>
array(7) {
["orderid"]=>
string(9) "198397652"
["created"]=>
string(19) "2014-11-14 15:10:10"
["ordertype"]=>
string(3) "Buy"
["price"]=>
string(10) "0.00517290"
["quantity"]=>
string(10) "0.00100000"
["orig_quantity"]=>
string(10) "0.00100000"
["total"]=>
string(10) "0.00000517"
}
[1]=>
array(7) {
["orderid"]=>
string(9) "198397685"
["created"]=>
string(19) "2014-11-14 15:10:13"
["ordertype"]=>
string(3) "Buy"
["price"]=>
string(10) "0.00517290"
["quantity"]=>
string(10) "0.00100000"
["orig_quantity"]=>
string(10) "0.00100000"
["total"]=>
string(10) "0.00000517"
}
[2]=>
array(7) {
["orderid"]=>
string(9) "198398295"
["created"]=>
string(19) "2014-11-14 15:11:14"
["ordertype"]=>
string(3) "Buy"
["price"]=>
string(10) "0.00517290"
["quantity"]=>
string(10) "0.00100000"
["orig_quantity"]=>
string(10) "0.00100000"
["total"]=>
string(10) "0.00000517"
}
}
}
我怎么会去[ “总”]和#3补充呢? [ “总”] + 3?
你能否详细说明世界卫生大会这个'['total'] + 3'的意思是。 – sln 2014-11-14 22:47:18