2012-07-23 62 views
1

我已经编写了一个程序,在一个文本文件中查找有效的电子邮件地址,该文件中有许多电子邮件,其中有效的&无效。C++ subString POS

&然后在另一个文本文件中输出vaild电子邮件。

我遇到的问题是创建一个子字符串或对象,它将读取@符号&左边的行,如果有多个“。”,则为true。

例如:阅读这行文字作为一个有效的电子邮件 - [email protected]

&

,如果有更多的 '' @符号读取为false后。 这里是我的代码:

#include<iostream> 
#include<string> 
#include<fstream> 
using namespace std; 
const string DEFAULT_INPUT_FILENAME="fileContainingEmails.txt"; 
const string DEFAULT_OUTPUT_FILENAME="copyPasteMyEmails.txt"; 
const int N=1000; //assuming atmost 1000 email 

//function prototypes 
bool isNotDuplicateEmail(string emails[], int emailCount, string emailTemp); 
bool isValidEmail(string emails[], string emailTemp); 
void WriteToFile(string emails[], int emailCount, string outputFile); 
void DisplayEmailsToConsole(string emails[], int emailCount); 
bool isValidEmailChar(char c); 
int countOccurenceOfAt(string emailTemp); 
int countOccurenceOfDot(string emailTemp); 

int main() 
{ 
    //variable declaration 
    ifstream fin; 
    string inputFile; 
    string outputFile; 
    int emailCount=0; 
    string emails[N]; 


    //ask user for input and output file name 
    cout<<"Enter input file name: "; 
    getline(cin,inputFile); 
    cout<<"Enter output file name: "; 
    getline(cin,outputFile); 

    //check for default names 
    if(inputFile=="") 
     inputFile=DEFAULT_INPUT_FILENAME; 
    if(outputFile=="") 
     outputFile=DEFAULT_OUTPUT_FILENAME; 

    cout<<"Input File Name = "<<inputFile<<endl; 
    cout<<"Output File Name = "<<outputFile<<endl; 

    //open input file 
    fin.open(inputFile.c_str()); 
    //if file does not exists, display error message and return 
    if(!fin) 
    { 
     cout<<"ERROR: "<<inputFile<<" doen not exists."<<endl; 
     return 1; 
    } 

    string emailTemp; 
    /*read each line from file, and if it is not a duplicate email and a valid email 
    then add it to email list and increment count*/ 
    while(getline(fin,emailTemp)) 
    { 
     if(isNotDuplicateEmail(emails,emailCount,emailTemp) && isValidEmail(emails,emailTemp)) 
     { 
      emails[emailCount]=emailTemp; 
      emailCount++; 
     } 
    } 
    //close input file 
    fin.close(); 

    //call function to write emails to output file and console 
    if(emailCount>0) 
    { 
     WriteToFile(emails, emailCount, outputFile); 
     cout << endl << emailCount << " email addresses were found, and copied to the file " << outputFile<<endl; 
     DisplayEmailsToConsole(emails, emailCount); 
    } 
    else 
    { 
     cout << "Sorry, no email addresses were found in the file " << inputFile << endl; 
    } 


    cout << endl<< "Press ENTER to continue..." << endl; 
    cin.get(); 
    return 0; 
} 

bool isNotDuplicateEmail(string emails[], int emailCount, string emailTemp) 
{ 
    /*Check each email address and if a duplicate email is found, return false*/ 
    /*If email is not a duplicate email, return true*/ 
    for(int i=0;i<emailCount;i++) 
    { 
     if(emailTemp==emails[i]) 
      return false; 
    } 
    return true; 
} 
bool isValidEmail(string emails[], string emailTemp) 
{ 
    if(emailTemp=="") 
     return false; 
    /*If there are more than 1 @*/ 
    if (countOccurenceOfAt(emailTemp)!=1) 
     return false; 
    /*If there are more than 1 .*/ 
    if(countOccurenceOfDot(emailTemp)!=1) 
     return false; 


    int index1=-1; 
    int index2=-1; 


    //check each character for valid email char 
    for (int i=0; i<emailTemp.size(); i++) 
    { 
     if(!isValidEmailChar(emailTemp[i])) 
      return false; 
    } 

    //find index of @ and . 
    index1=emailTemp.find_first_of('@'); 
    index2=emailTemp.find_first_of('.'); 

    if(index1<1) 
     return false; 
    if(index2<index1) 
     return false; 
    if((index2-index1)==1) 
     return false; 

    if(((emailTemp.size()-1)-index2)==0) 
     return false; 

    return true; 
} 

bool isValidEmailChar(char c) 
{ 
    /* check for valid email characters 0-9, @, ., A-Z, a-z, _, +, - */ 
    if(c>='0' && c<='9') 
     return true; 
    if(c>='A' && c<='Z') 
     return true; 
    if(c>='a' && c<='z') 
     return true; 
    if(c=='@' || c=='.' || c=='_' || c=='+' || c=='-') 
     return true; 

    return false; 

} 

/*Function to count occurence of @ in email address*/ 
int countOccurenceOfAt(string emailTemp) 
{ 
    int count=0; 
    for(int i=0;i<emailTemp.size();i++) 
    { 
     if(emailTemp[i]=='@') 
      count++; 
    } 
    return count; 
} 

/*Function to count occurence of . in email address*/ 
int countOccurenceOfDot(string emailTemp) 
{ 
    int count=0; 
    for(int i=0;i<emailTemp.size();i++) 
    { 
     if(emailTemp[i]=='.') 
      count++; 
    } 
    return count; 
} 

void DisplayEmailsToConsole(string emails[], int emailCount) 
{ 
    /*Display console message and then display each email address, one at a line*/ 
    cout << endl << endl << "You can open the output file and copy/paste its contents into the \"to\", \"cc\", or \"bcc\" field of any email message. It is best to use the \"bcc\" field so that everyone's email address does not appear in the message, to protect their privacy"<<endl; 
    cout << endl << "Email List is: "<< endl; 
    for (int i=0; i<emailCount; i++) 
    { 
     cout << emails[i] << endl; 
     cout << endl; 
    } 
} 

void WriteToFile(string emails[], int emailCount, string outputFile) 
{ 
    /*Open file and write each email address to output file followed by ; */ 
    ofstream fout; 
    fout.open(outputFile.c_str()); 
    for(int i=0; i<emailCount; i++) 
    { 
     fout << emails[i] << "; " << endl; 
    } 
    //close file 
    fout.close(); 
} 
+6

这是很多代码。你应该把它缩小一点,'WriteToFile' f.ex.在关于子串和输入验证的问题中只是噪声。 (恕我直言) – jrok 2012-07-23 17:54:59

+0

看看这个其他问题:http://stackoverflow.com/questions/201323/using-a-regular-expression-to-validate-an-email-address – betabandido 2012-07-23 18:09:22

回答

1

如果你需要知道的是,如果有@符号前面多期,然后就去做:

if (email.find_first_of('.') == email.find_last_of('.')) 

如果表达式返回true,那么你就知道该字符串只有一个周期(或没有)。

+0

@符号之前的@符号?这会为“[email protected]”返回false。 – Marlon 2012-07-23 18:16:54

+0

让“email”等于@符号前的地址部分。所以,让“email”等于“Jimmy.Cole” – 2012-07-23 18:21:33

+0

嘿迈克,我不知道我应该在哪里放置这行代码。我有一个文本文件中只有有限数量的有效或真实电子邮件的多个电子邮件。我的程序读取真正的电子邮件罚款1例外。它不能阅读电子邮件,如[email protected] bc。在@符号之前。我似乎无法找到正确的路线来放置此。我觉得我的脑袋超负荷或什么的。 – 2012-07-23 20:41:03

1

下面的代码是从书Secure Programming Cookbook for C and C++

#include <string.h> 

int spc_email_isvalid(const char *address) { 
    int  count = 0; 
    const char *c, *domain; 
    static char *rfc822_specials = "()<>@,;:\\\"[]"; 

    /* first we validate the name portion ([email protected]) */ 
    for (c = address; *c; c++) { 
    if (*c == '\"' && (c == address || *(c - 1) == '.' || *(c - 1) == 
     '\"')) { 
     while (*++c) { 
     if (*c == '\"') break; 
     if (*c == '\\' && (*++c == ' ')) continue; 
     if (*c <= ' ' || *c >= 127) return 0; 
     } 
     if (!*c++) return 0; 
     if (*c == '@') break; 
     if (*c != '.') return 0; 
     continue; 
    } 
    if (*c == '@') break; 
    if (*c <= ' ' || *c >= 127) return 0; 
    if (strchr(rfc822_specials, *c)) return 0; 
    } 
    if (c == address || *(c - 1) == '.') return 0; 

    /* next we validate the domain portion ([email protected]) */ 
    if (!*(domain = ++c)) return 0; 
    do { 
    if (*c == '.') { 
     if (c == domain || *(c - 1) == '.') return 0; 
     count++; 
    } 
    if (*c <= ' ' || *c >= 127) return 0; 
    if (strchr(rfc822_specials, *c)) return 0; 
    } while (*++c); 

    return (count >= 1); 
}