如何将这2个SQL查询合并为一个SQL查询

Question

我正在使用SQL Server 2014，并且我有两个分别运行的查询，现在我需要连接这些查询，以便拥有一个输出。

查询1立场如下：

USE MyDatabase 

SELECT a.ReservationStayID, 
    c.Createdon, 
    a.FirstName + ' ' + a.LastName AS 'Name', 
    b.PropertyCode AS'Property', 
    b.ReservationStatus AS 'Status', 
    d.rsl_rateplan AS 'Rate Plan Code', 
    d.rsl_mealplan, 
    d.rsl_roomtype, 
    b.MarketSegmentCode AS 'Market Segment', 
    e.TravelAgencyTypeCode AS 'Source of Business', 
    a.ArrivalDate AS 'Date of Arrival', 
    a.DepartureDate AS 'Date of Departure', 
    (SELECT DATEDIFF (day,ArrivalDate,DepartureDate) 
    FROM ReservationStay c 
    WHERE c.ReservationStayID = a.ReservationStayID) AS 'Nights', 
    c.AdultCount AS 'Adult', 
    c.ChildCount AS 'Child', 
    b.GuestCount AS 'Guest', 
    d.rsl_reasonstay, 
    c.TaProfileID, 
    c.PMSConfirmationNumber, 
    c.CurrencyCode As 'Currency', 
    d.rsl_nationality AS 'Nationality', 
    d.rsl_country AS 'Country of Residence', 
    d.rsl_totalroomrate, 
    e.Name AS 'Tour Operator', 
    e.CountryCode AS 'Market Code',  
    g.CountryGroup AS 'Market', 


(SELECT avg(RateAmount)/1.15 
    FROM ReservationStayDate f 
    where f.ReservationStayID = a.ReservationStayID) AS 'Rate Amount Excl.VAT', 

    c.TAProfileID2, 
    e2.Name AS 'Booking Origin (1)', 
    g2.CountryGroup AS 'Booking Origin (2)' 




FROM GuestNameInfo a 
JOIN GuestStaySummary b ON a.ReservationStayID = b.ReservationStayID 
LEFT JOIN ReservationStay c ON c.ReservationStayID = b.ReservationStayID 
LEFT JOIN P5RESERVATIONLIST d ON d.rsl_code = b.ReservationStayID 
LEFT JOIN TravelAgency e ON e.TravelAgencyID = c.TAProfileID 
LEFT JOIN Market g ON e.CountryCode = g.CountryCode 
LEFT JOIN TravelAgency e2 ON e2.TravelAgencyID = c.TAProfileID2 
LEFT JOIN Market g2 ON e2.CountryCode = g2.CountryCode 


WHERE a.PrimaryGuest='+' and d.rsl_primaryguest='+' 

ORDER by a.ReservationStayID 

而第二个查询：

use MyDatabase 

select * 

FROM (SELECT 
    ReservationStayID,count(reservationstayid) AS [Nights Spent], 
    datename(m,StayDate)+' '+ cast(datepart(yyyy,StayDate) as varchar) as [MTH], 
    avg(RateAmount) as [Rate], 
    CreatedOn 

from ReservationStayDate 

GROUP BY ReservationStayID,STAYDATE,RATEAMOUNT,CreatedOn 

) AS S 

ORDER by ReservationstayID 

如果是这样的INNER JOIN，OUTER JOIN或一个完全不同的语法？

附加信息：

好，要更明确，这里有几个指针。 ReservationStayDate表列出按住宿日期保留的住宿人数（StayDate）。因此，如果客人在2014年10月31日至2014年11月4日之间逗留，ReservationStayDate表格每晚将显示4行（即：2014-10-31,2014-11-01,2014-11-02和2014-11-03）。

当我运行第一个查询时，我的输出对于每个来宾都是一行。现在，我需要为2个月以上（如上例所示）夜间出现的客人输出我的输出，其中添加的列名称为“MTH”（实际上显示月份和年份）和“已用夜间”。因此，输出将看起来像这样的客人谁花所有的夜晚在同一个月，并为那些谁超过2个月重叠：

ReservationStayId  CreatedOn........ DateOfArrival DateOfDeparture MTH  Nights 
    250         2014-09-05 2014-09-07 Sept 2014 2 
    285         2014-10-31 2014-11-04 Oct 2014  1 
    285         2014-10-31 2014-11-04 Nov 2014  3 

我希望我做了它一个更清晰一点了解。如果没有，请评论，我会添加更多的具体信息。

Answer 1

您可以随时使用派生表。这是一个你加入的查询，就像你加入一个表一样。

SELECT 
    ... 
    x.[Nights Spent], 
    x.[MTH], 
    x.[Rate], 
    x.CreatedOn, 
    x.[DateOfArrival], 
    x.[DateOfDeparture] 
FROM GuestNameInfo a 
JOIN GuestStaySummary b ON a.ReservationStayID = b.ReservationStayID 
LEFT JOIN ReservationStay c ON c.ReservationStayID = b.ReservationStayID 
LEFT JOIN 
(
    SELECT 
    ReservationStayID, 
    datename(m,StayDate) + ' ' + cast(datepart(yyyy,StayDate) as varchar) as [MTH] 
    count(*) AS [Nights Spent], 
    avg(RateAmount) as [Rate], 
    min(CreatedOn) as CreatedOn, 
    min(StayDate) as [DateOfArrival], 
    max(StayDate) as [DateOfDeparture] 
    FROM ReservationStayDate 
    GROUP BY ReservationStayID, datename(m,StayDate) + ' ' + cast(datepart(yyyy,StayDate) as varchar) 
) x ON x.ReservationStayID = b.ReservationStayID 
... 

正如在评论你的要求已经提到的，你的第二个查询的就是没有意义 编辑：我已经按照您的要求修改改变了第二个查询。

如前所述，第一个查询是关于外部连接的中断。还有一个建议：使用可读的别名，而不是a，b，c，但可能是GuestNameInfo的gni，GuestStaySummary的gss等等。只要你想知道列所属的表是什么，就不必查找from/join子句。

Answer 2

尝试这个希望进展....

select 
a.ReservationStayID, 
c.Createdon, 
a.FirstName + ' ' + a.LastName AS 'Name', 
b.PropertyCode AS'Property', 
b.ReservationStatus AS 'Status', 
d.rsl_rateplan AS 'Rate Plan Code', 
d.rsl_mealplan, 
d.rsl_roomtype, 
b.MarketSegmentCode AS 'Market Segment', 
e.TravelAgencyTypeCode AS 'Source of Business', 
a.ArrivalDate AS 'Date of Arrival', 
a.DepartureDate AS 'Date of Departure', 
(SELECT DATEDIFF (day,ArrivalDate,DepartureDate) 
FROM ReservationStay c 
WHERE c.ReservationStayID = a.ReservationStayID) AS 'Nights', 
c.AdultCount AS 'Adult', 
c.ChildCount AS 'Child', 
b.GuestCount AS 'Guest', 
d.rsl_reasonstay, 
c.TaProfileID, 
c.PMSConfirmationNumber, 
c.CurrencyCode As 'Currency', 
d.rsl_nationality AS 'Nationality', 
d.rsl_country AS 'Country of Residence', 
d.rsl_totalroomrate, 
e.Name AS 'Tour Operator', 
e.CountryCode AS 'Market Code',  
g.CountryGroup AS 'Market',-------change to g.CountryName to obtain Original Markets 
c.TAProfileID2, 
e2.Name AS 'Booking Origin (1)', 
g2.CountryGroup AS 'Booking Origin (2)' 

,s.*, 

(SELECT avg(RateAmount)/1.15 
FROM ReservationStayDate f 
where f.ReservationStayID = a.ReservationStayID) AS 'Rate Amount Excl.VAT' 




from GuestNameInfo a 
JOIN GuestStaySummary b ON a.ReservationStayID = b.ReservationStayID 
LEFT JOIN ReservationStay c ON c.ReservationStayID = b.ReservationStayID 
LEFT JOIN P5RESERVATIONLIST d ON d.rsl_code = b.ReservationStayID 
LEFT JOIN TravelAgency e ON e.TravelAgencyID = c.TAProfileID 
    LEFT JOIN Market g ON e.CountryCode = g.CountryCode 
    LEFT JOIN TravelAgency e2 ON e2.TravelAgencyID = c.TAProfileID2 
    LEFT JOIN Market g2 ON e2.CountryCode = g2.CountryCode 
inner join 
    (SELECT 
    ReservationStayID,count(reservationstayid) AS [Nights Spent], 
    Convert(varchar,datename(m,StayDate)+' '+ cast(datepart(yyyy,StayDate)) as [MTH], 
    avg(RateAmount) as [Rate], 
    CreatedOn 

from ReservationStayDate 

GROUP BY ReservationStayID,STAYDATE,RATEAMOUNT,CreatedOn 

) AS S on s.ReservationStayID=a.ReservationStayID 

WHERE a.PrimaryGuest='+' and d.rsl_primaryguest='+' 
and f.ReservationStayID = a.ReservationStayID) AS 'Rate Amount Excl.VAT', 

ORDER by ReservationstayID