打印文本在一行

Question

下面的代码打印这样的文字：

John 
    Smith 
    02/07/1234 

首先，它缩进两个行，我将如何改变代码以打印为： John Smith 02/07/1234上一个线？

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print (forename, surname, birthdate) 

Answer 1

尝试：

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print("{} {} {}".format(forename.strip(' \t\n\r'), surname.strip(' \t\n\r'), birthdate.strip(' \t\n\r'))) 

的.strip（ '\ t \ n \ r'）除去开头和结尾的标签和空格，该.format（）格式，您的字符串以可控的方式进行打印。

Answer 2

使用.join并从每个名称中去掉空格。

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print(' '.join([forename.strip(), surname.strip(), birthdate.strip()])) 

Answer 3

由于您的问题没有明确指定的Python，你可能想知道，你不需要任何程序可言，如果你是一个unixoid系统（BSD，Linux和Mac OSX版）上：只使用paste shell命令：

paste -d ";" forename surname birthday 

将产生

John;Smith;02/07/1234 

如果不指定-d标志，标签将被用于条目分开。您可以了解更多关于paste这里：https://en.wikipedia.org/wiki/Paste_(Unix)

Answer 4

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print (forename, surname, birthdate, end=' ')