我需要更换这个HTML代码的链接替换词?在PHP
在控制面板中我看不到演员表我只看到这一点:[xfvalue_actors]
,我试图取代,因为这:
<a href="http://myfilms.ga/actor/<?php $str = '[xfvalue_actors]'; echo preg_replace('/, /', '"></a><a href="http://myfilms.ga/actor/', $str, 20); ?>/">[xfvalue_actors]</a><br />
,但我得到它:
<a href="http://myfilms.ga/actor/Mamoru Miyano"></a><a href="http://myfilms.ga/actor/Kappei Yamaguchi"></a><a href="http://myfilms.ga/actor/Aya Hirano">Mamoru Miyano, Kappei Yamaguchi, Aya Hirano</a><br />
你可以修改渲染'[xfvalue_actors]'宏? – Gordon 2014-10-18 10:28:01